3 years ago

A sixth number will be added to the list. What must it be in order for the mean to be 12?

Mathematics

2 answers:

Nataliya [291]3 years ago

7 0

The sixth number should be 16 in order for the mean to be 12

Effectus [21]3 years ago

4 0

Answer:

Step-by-step explanation:

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QveST [7]

$De finition:\\\sqrt{a}=b\ \iff b^2=a\\=====================\\\\$

$625|5\\125|5\\.\ 25|5\\.\ \ 5|5\\.\ \ 1|\\\\625=5\times5\times5\times5=5^2\times5^2\\\\\sqrt{625}=\sqrt{5^2\times5^2}=(*)\\-------------------------------\\use:\ \sqrt{a\times b}=\sqrt{a}\times\sqrt{b}\ and\ \sqrt{a^2}=a\ for\ a\geq0\\-------------------------------\\(*)=\sqrt{5^2}\times\sqrt{5^2}=5\times5=\boxed{25}$

$Other\ solution:\\\\\sqrt{625}=25\ because\ 25^2=25\times25=625$

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Step-by-step explanation:

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