Jose collected 485 books over the summer.
The total number of books that he had at the end of the summer was 525. You can find this by multiplying 15 by 35, because each library received 35 books. Then, you need to subtract the 40 that he started with.
x = 35(15) - 40
Answer: The volume is 2143.57
Step-by-step explanation:
v= 4/3 * 3.14 * 8^3
v = 2143.57
The answer to (6.8*10^4) + (9.24*10^5) is 734
Let P be the population proportion, p be the sample proportion, n be the sample size.
A manufacturer claims that fewer than 6% of its fax machines are defective. It means P=0.06
Sample size n=97 and sample proportion p=0.05
The hypothesis to be tested is
H0: P ≥ 0.06 V/s Ha: P < 0.06
Here the hypothesis for testing population proportion we use z test statistics. Z test statistics is give by
Z = ![\frac{p -p_{0}}{\sqrt{p_{0}(1-p_{0})/n}}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bp%20-p_%7B0%7D%7D%7B%5Csqrt%7Bp_%7B0%7D%281-p_%7B0%7D%29%2Fn%7D%7D%20%20%20%20%20%20)
Where p =sample proportion = 0.05
p0 = hypothesized proportion value =0.06
Using given values into test statistics we get
Z = ![\frac{0.05 -0.06}{\sqrt{0.06(1-0.06)/97}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B0.05%20-0.06%7D%7B%5Csqrt%7B0.06%281-0.06%29%2F97%7D%7D%20%20%20%20%20%20)
Z = -0.41
The p-value for left tailed alternative hypothesis is given by
P-value = P(z < z cal)
where zcal = Z test statistics value
Here zcal = -0.41
P-value = P(Z < -0.41)
Using z score table to find probability below z=-0.41
P-value = 0.3409
P-value for testing the given claim is 0.3409
Answer:5
Step-by-step explanation: