Answer:
I think it's B because I think there can only be one outlier. idk for sure but I think i remember learning that
Step-by-step explanation:
First find the the value of t where the curve intersects the Y-axis. This is when x = 0.
x = t^2 - 2t = 0 = t(t - 2)
So t= 0 and t = 2
dA = (0 - x)*dy .... Since the curve has negative x in this region
y = SQRT(t) and dy = [(1/2)/SQRT(t)]dt
dA = [2t - t^2][(1/2)/SQRT(t)]dt
dA = [t^(1/2) - (1/2)t^(3/2)]dt
Integrate to get: A = (2/3)t^(3/2) - (1/5)t^(5/2)
Now evaluate from t= 0 to t = 2.
Area = [(2/3)2^(3/2) - (1/5)2^(5/2)] - [0]
<span>
Area = SQRT(2)[4/3 - 4/5]
</span><span>
Area = SQRT(2)[8/15) = 0.754
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
- Total time=5h
- Time devoted for mathematics and science=2h
Let Time devoted for others be x
12x-4320=120
12x=120+4320
12x=4440
x=370
The correct answer is D.12
