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AlladinOne [14]
3 years ago
5

PLEASE HELP The following sentence shows one of the steps to construct a regular hexagon inscribed in a circle.

Mathematics
2 answers:
Whitepunk [10]3 years ago
7 0

Answer:

The width of the compass needs to be set to equal the radius of the circle.

Step-by-step explanation:

The statement that should be added to make this step correct is - The width of the compass needs to be set to equal the radius of the circle.

<u>You can see the complete steps below:</u>

1. Mark a point anywhere on the circle, which will be the first vertex of the hexagon.

2. Now set the compass on this vertex and set the width of the compass to the center of the circle. This setting is the radius of the circle.

3. Make an arc across the circle that will be the next vertex of the hexagon.

4. Now we will move the compass on to the next vertex and draw another arc. Now the third vertex of the hexagon will be drawn.

5. We continue the above step until we get all six vertices.

6. Lastly, we draw a line between each successive pairs of vertices. This forms the hexagon.

ludmilkaskok [199]3 years ago
3 0
Should be:

<span>The width of the compass needs to be set to equal the radius of the circle

................................................................................</span>
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Step-by-step explanation:

12 - hour conversion.

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What is the sum of the interior angles of nonregular hexagons?
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A card is drawn at random from a well-shuffled pack of 52 cards. Find the probability that the card drawn is neither a red card
Reil [10]
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The following exchange rate is given: £1=1.35 Dollars. Convert £9 into dollars
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3 years ago
Hurry please!!! Fast response
AlladinOne [14]

Answer:

A.

SA= \frac{2}{3} \pi rl+16 \pi r^2

Step-by-step explanation:

Surface area of the original cone

SA= \pi r l + \pi r^2... (1)

When, radius is quadrupled and slant height is reduced to one sixth

i. e. \: \:r = 4r\: \: \&\:\: l= \frac{1}{6}l

Plug the above values of r and l in equation (1), new surface area becomes:

SA= \pi (4r)\times \frac{1}{6} l+ \pi (4r)^2

SA= \frac{4}{6} \pi rl+16 \pi r^2

\huge \purple {\boxed {SA= \frac{2}{3} \pi rl+16 \pi r^2}}

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