PLEASE HELP!! I'm stuck on this

Mathematics

1 answer:

Kamila [148]3 years ago

4 0

T=0=>initial
s (0)=4.5=9/2
=>s(t)=-16t^2+64+9/2
use s(-b/2a) to find height
it will take -b/2a seconds to reach that height
n I tell a,b coefficients of some
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The sum of the first 150 negative integers is represented using the expression What is the sum of the first 150 negative integer

Kamila [148]

Answer:

C. -11,325

Step-by-step explanation:

To know the answer, is convenient to replace some values of "n" in the sum $\sum_{(n=1)}^{150}[-1-(n-1)]$ .

The result would appear after adding up every value of the expression $\sum_{(n=1)}^{150}[-1-(n-1)]$ when n=1,2,3.....,150.
When n=1, the expression takes the value of (-1): $[-1-(1-1)]= (-1)-0=-1$ .
When n=2, the expression takes the value of (-2): $[-1-(2-1)]=-1-1=-2$ .
Following this way, for every n, we will obtain -n, then, the sum will be: $-1-2-3-4-5-6-...-150$ . This sum can actually be expressed as $\sum_{n=1}^{150}(-n)$ , which is the result of solving the initial expression of the sum $-1-(n-1)=-1-n+1=-n$ .
Finally, the sum of n=-1 to n=-150 equals -11,325.