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GenaCL600 [577]
3 years ago
8

The safe load for a certain horizontal beam used to hold up part of a building varies inversely as the length between the

Mathematics
1 answer:
Misha Larkins [42]3 years ago
6 0

The statement is true.

Answer: Option 1.

<u>Explanation:</u>

An horizontal beam is constantly flat and has a consistent cross-segment. Notwithstanding normal shaft parameters, bar has the accompanying properties: Direction. A flat shaft might be situated either along the worldwide X-hub or worldwide Y-pivot.

A horizontal beam is used to hold a building up right and to give the support to the building. But the length of the horizontal beam differs in an inverse way between the supports.

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40 square meters

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Pls help I am struggling
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3 years ago
Last year, a soft drink manufacturer had 22% of the market. In order to increase their portion of the market, the manufacturer h
N76 [4]

Answer:

Critical value zc = 1.6449.

As the test statistic z=1.3881 is smaller than the critical value zc=1.6449, it falls in the acceptance region and the null hypothesis is failed to be rejected.

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that more than 22% of the population will like the new soft drink.

Then, the null and alternative hypothesis are:

H_0: \pi=0.22\\\\H_a:\pi>0.22\\

The significance level is 0.05.

The sample has a size n=400.

The sample proportion is p=0.25.

p=X/n=100/400=0.25

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.22*0.78}{400}}\\\\\\ \sigma_p=\sqrt{0.000429}=0.0207

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.25-0.22-0.5/400}{0.0207}=\dfrac{0.0288}{0.0207}=1.3881

As this is a right-tailed test, there is only one critical value and it is, for a significance level of 0.05, zc=1.6449.

As the test statistic z=1.3881 is smaller than the critical value zc=1.6449, it falls in the acceptance region and the null hypothesis is failed to be rejected.

3 0
3 years ago
How many integers from 100 to 999 can be written in base ten without using the digit 7?
const2013 [10]

The number of integers from 100 to 900 that can be written in base ten without using the digit 7 is 648.

From 100 to 999, all integers are three (3) digit numbers and available digits are (0, 1, 2, 3, 4, 5, 6, 7, 8, 9).

It implies that the total number of digits is 9. The next thing to do will be to arrange the 9 digits in three (3) places in such a way that repetition is allowed.

In the first place;

  • the number of ways the number can be positioned since it can't be zero and seven =  8.

Hence, the first chance is 8 out of 10 chance.

In the second and third place;

  • the chances are =  9

∴

The number of integers from 100 to 900 that can be written in base ten without using the digit 7 is:

= 8 × 9 × 9

= 648

Therefore, the number of integers from 100 to 900 that can be written in base ten without using the digit 7 is 648.

Learn more about integers here:

brainly.com/question/15276410?referrer=searchResults

3 0
3 years ago
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