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GenaCL600 [577]
3 years ago
8

The safe load for a certain horizontal beam used to hold up part of a building varies inversely as the length between the

Mathematics
1 answer:
Misha Larkins [42]3 years ago
6 0

The statement is true.

Answer: Option 1.

<u>Explanation:</u>

An horizontal beam is constantly flat and has a consistent cross-segment. Notwithstanding normal shaft parameters, bar has the accompanying properties: Direction. A flat shaft might be situated either along the worldwide X-hub or worldwide Y-pivot.

A horizontal beam is used to hold a building up right and to give the support to the building. But the length of the horizontal beam differs in an inverse way between the supports.

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 The area of a circle is less than 1 dm². Find the radius of the circle. The area of a circle is less than 1 dm². Find the rad
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\bf \textit{area of a circle}\\\\&#10;A=\pi r^2\qquad &#10;\begin{cases}&#10;\textit{let's say the Area is 1 exactly}\\&#10;A=1&#10;\end{cases}\implies 1=\pi r^2&#10;\\\\\\&#10;\cfrac{1}{\sqrt{\pi }}=r

if you drop the radius to less than that, then the Area will also drop to less than 1 unit, in this case it happens to be a decimeter
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3 years ago
Find the midpoint and distance between (5,1) and (-15,11)
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Answer:

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4 0
3 years ago
From a box containing 10 cards numbered 1 to 10, four cards are drawn together. The probability that their sum is even is 21 21
ankoles [38]

Answer:

Step-by-step explanation:

We know that between 1 to 10 there are 5 even and 5 odd numbers.

We could get 4 even cards , 4 odd cards or 2 odd and 2 even cards

Let´s check all this combinations

Case 1: When all 4 numbers are even:  

We are going to take 4 of the 5 even numbers in the box so we have

5C4=5

Case 2: When all 4 numbers are odd:  

We are going to take 4 of the 5 odd numbers in the box, so we have

5C4=5

Case 3: When 2 are even and 2 are odd:

We are giong to take 2 from 5 even and odd cards in the box so we have

 

5C2 * 5C2

Remember that we obtain the probability from

\frac{Number-of-favourable-Outcome}{Total-number-of-outcomes}

So we have the number of favourable outcomes but we need the Total cases for drawing four cards, so we have that:  

We are taking 4 of the 10 cards:

10C_4=210

Hence we have that the probability that their sum is even

\frac{5+5+100}{210}=\frac{11}{21}

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3 years ago
10. If $5000 is invested in an account that compounds interest
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Answer:

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3 years ago
For a consumer to obtain a 10% discount, he must spend an amount
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Answer:

the answer is 180 dollars

Step-by-step explanation:

20 is 10% of 200 so just subtract that

3 0
2 years ago
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