If 5 , 3 = 28 9 , 1 = 810 8 , 7 = 115 6 , 2 = 48 then 7 , 5 = ?
2 answers:
You might be interested in
Answer:
A quadratic equation can be written as:
a*x^2 + b*x + c = 0.
where a, b and c are real numbers.
The solutions of this equation can be found by the equation:
Where the determinant is D = b^2 - 4*a*c.
Now, if D>0
we have the square root of a positive number, which will be equal to a real number.
√D = R
then the solutions are:
Where each sign of R is a different solution for the equation.
If D< 0, we have the square root of a negative number, then we have a complex component:
√D = i*R
We have two complex solutions.
If D = 0
√0 = 0
then:
We have only one real solution (or two equal solutions, depending on how you see it)
I believe it's<span> 8cos(x)⁸ - 16cos(x)⁶ + 10cos(x)⁴ - 2cos(x)².
</span>
<span>
Alternately, you can write [</span><span><span>1 / (tan(2x) - cot(2x))] + [cos(8x) / (tan(2x) - cot(2x))].
</span></span>
<span><span>
</span></span>
</span>
Alternately, you can write [</span><span><span>1 / (tan(2x) - cot(2x))] + [cos(8x) / (tan(2x) - cot(2x))].
</span></span>
</span></span>