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kogti [31]
3 years ago
13

5. The circumference of a base of a cylinder is 176cm and its height is 60cm,

Mathematics
2 answers:
Aliun [14]3 years ago
5 0

Answer:

the answer is 146

Step-by-step explanation:

the radius is 88

Levart [38]3 years ago
4 0

Answer:i don,t have the answer but i can tell you this with volume you have to do length  times width times height

Step-by-step explanation:

sorry that i don,t have the answer that you were hoping for

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Solve for x.<br>A. x =9<br>B. x = 3<br>C. x = 4<br>D. x = 27
meriva
Your formula for this is 9^{2} =x(24+x) and 81=24x+ x^{2}.  Get everything on one side of the equals sign, set it equal to 0 and factor.  When you do this you get (x-3)(x+27). The Zero Product Property rule tells us that either x-3 = 0 or x+27 = 0 and that x = 3 and -27.  The only thing in math that will NEVER be negative besides time is distance/length, therefore, x cannot be 27 and has to be 3.
8 0
3 years ago
What is the 20th term of the linear sequence?<br><br>1,7,13,19,25
Nimfa-mama [501]

Answer:

115

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = 7 - 1 = 13 - 7 = 19 - 13 = 25 - 19 = 6

This indicates the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 1 and d = 6 , thus

a₂₀ = 1 + (19 × 6) = 1 + 114 = 115

4 0
3 years ago
Which of the following is a composite number?<br> 31<br> 80<br> 2
Nonamiya [84]

Answer:

80

Step-by-step explanation:

80 can be divided by 2, 4, 5, 8, 10, 16, 20, 40

7 0
3 years ago
Why does 5xy3<br> have a degree of 4?
kolezko [41]
The degree is 4 because the term shown has TWO variables, while y has an exponent of 3, x has an exponent of 1, add the exponents of the variables to find the degree
5 0
3 years ago
Part of the proceeds from a garage sale was $455 worth of $5 bills and $20 bills. If there were 6 more $5 bills than 20$ bills f
Feliz [49]

Answer:

\large \boxed{\text{17 \$20 bills and 23 \$5 bills}}

Step-by-step explanation:

               Let x = the number of $20 bills.

     Then x + 6 = the number of $5 bills  and

20x + 5(x +  6) = 455

\begin{array}{rcl}20x + 5(x + 6) & = & 455\\20x + 5x + 30 & = & 455\\25x + 30 & = & 455\\25x & = & 425\\x & = &\dfrac{425}{25}\\\\x & = &\mathbf{17}\\\end{array}

                    x = 17 = number of $20 bills

x + 6 = 17 + 6 = 23 = number of $5 bills

\text{There were }\large \boxed{\textbf{17 \$20 bills and 23 \$5 bills}}

Check:

\begin{array}{rcl}20\times17+ 5(17 + 6) & = & 455\\340 + 5\times23& = & 455\\340 + 115 & = & 455\\455 & = & 455\\\end{array}

OK.

7 0
3 years ago
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