The area of flag b is the greatest.
<u><em>Explanation:</em></u>
Area of triangle =
Area of parallelogram = base * height
<u>For flag A:</u>
It is a triangle with base = b and height = a
Area of flag A = square units
<u>For flag B:</u>
It is a parallelogram with base = a and height = b
Area of flag B = a*b square units
<u>For flag C:</u>
It is a triangle with base = b and height = a
Area of flag C = square units
<u>From the above, we can conclude</u> that the area of the parallelogram (flag B) is the greatest
<h2><u><em>Question 2:</em></u></h2>The perimeter of flag C is shorter than that of flag A
<em><u>Explanation:</u></em>
Perimeter is the sum of the three sides of the figure
<u>For flag C:</u>
The three sides are given as a, b and c
Therefore, perimeter of flag c = a + b + c units
<u>For flag A:</u>
We are given two sides as b and c and we are given that the height is a
We know that in the given flag, the third side (the unknown slant one) will be longer than the height of the height of the triangle
Therefore, the third side = a + k where k is a constant
Therefore, perimeter of flag A = a + b + c + k units
<u>From the above, we can conclude that</u> the perimeter of flag C is shorter
Hope this helps :)