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JulijaS [17]
3 years ago
10

Which sequences could be described by the recursive definition LaTeX: a_{n+1}=3\cdot a_n-1a n + 1 = 3 ⋅ a n − 1

Mathematics
2 answers:
JulijaS [17]3 years ago
8 0

Answer:

an=3+an-1

2, 5, 14, 41, 122..

9

Step-by-step explanation:

zavuch27 [327]3 years ago
4 0

Answer:

<h2>2,6,18,54,162...</h2>

Step-by-step explanation:

The given expression is:

a_{n}=3 a_{n-1}

To find the right sequence, we have to find the value for n=1, n=2, n=3, n=4 and n=5, which are presented in the following operations, also we know that the first term is 2, we can begin from there:

a_{1}=2\\a_{2}=3(2)=6\\ a_{3}=3(6)=18\\ a_{4}=3(18)=54\\ a_{5}=3(54)=162

As you can see, the given expression represents a sequence where the next term is the triple than the term before.

As a result, we found the sequence 2, 6, 18, 54, 162...

Therefore the right answer is the last choice.

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Help no links please u^u
Veseljchak [2.6K]

Answer:

∠A= 80°

Step-by-step explanation:

if they are supplementary then put them equal to 180

7x + 3 +7x + 23 = 180

14x + 26 = 180

14x = 154

x= 11

now plug in

7(11)+3

77+3= 80

3 0
2 years ago
HELP!!! I CANT SEEM TO GET IT RIGHT!
miss Akunina [59]

Answer:

The speed is 16 kilometers per hour.

The cyclist will travel 80 kilometers in 5 hours.

4 0
2 years ago
Find an invertible matrix P and a matrix C of the form such that the matrix A has the form A. The eigenvalues of A are and with
Drupady [299]

Answer:

Hello your question is incomplete attached below is the correct question

and the solution

answer: A

Step-by-step explanation:

attached below is a detailed solution of the given problem

There exists P and C such that ( ∵ λ1 ≠ λ21 so A is diagonalizable )

5 0
2 years ago
A manager wants to select one group of 4 people from his 28 assistants.
Keith_Richards [23]

There are, 20475 different groups are possible if the manager wants to select one group of 4 people from his 28 assistants.

<h3>What is permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

We have:

A manager wants to select one group of 4 people from his 28 assistants.

The total number of groups possible = C(28, 4)

= \rm \dfrac{28!}{4!(28-4)!}

After calculating:

= 20475

Thus, there are, 20475 different groups are possible if the manager wants to select one group of 4 people from his 28 assistants.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ1

8 0
1 year ago
In 1963, the United States Postal Service started using ZIP (Zone Improvement Plan) codes. Each ZIP code is a sequence of five d
bija089 [108]
Here is how you find the number of possible U.S Zip codes. 
<span>Take note of this: There are 10 1 digit numbers: 0,1,2,3,4,5,6,7,8,9.
</span>And we have 5 slots. So in each slot, there can be 10 possible numbers. 
So let's put 10 in each blank slot. 
10, 10, 10, 10, 10.
Therefore, the final answer would be 100,000. There are 100,000 possibilities of different U.S zip codes. Hope this answer helps.
5 0
2 years ago
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