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Korvikt [17]
3 years ago
8

Two thirds of a number is 16 what is the number?

Mathematics
2 answers:
oee [108]3 years ago
8 0

Answer:

x=24

Step-by-step explanation:

We can set up an equation:

2/3 * x = 16

Multiplying both sides by the reciprocal of 2/3 to isolate the variable, we get

3/2 * 2/3 * x = 16* 3/2

1*x=24

x=24

yawa3891 [41]3 years ago
4 0
The answer to the question is 24.
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If f(x)=x/3 -2 and g(x)=3x^2+2x-6 find (f+g)(x)
umka21 [38]

Answer:

(f + g)(x) = 3x² + (7/3)x - 8

Step-by-step explanation:

To find (f + g)(x), you need to add both the f(x) and g(x) equations together.

f(x) = x/3 - 2 ..... which is equal to ... f(x) = (1/3)x - 2

g(x) = 3x² + 2x - 6

(f + g)(x) = ((1/3)x - 2) + (3x² + 2x - 6)          <----- Add both equations

(f + g)(x) = 3x² + (1/3)x + 2x - 2 - 6              <----- Rearrange (2 = 6/3)

(f + g)(x) = 3x² + (7/3)x - 8                           <----- Simplify similar terms

6 0
1 year ago
Amari has a previous balance of $691 on a credit card with a 17.1% APR compounded monthly. If he made a payment of $95 this mont
Marrrta [24]
691-95=596
596 X .171=101.9
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5 0
3 years ago
Read 2 more answers
Find the first five terms of the sequence given the following recursive formula:
forsale [732]

Answer:

The first five terms are;

-3,-7,11,-29,69

Step-by-step explanation:

The recursive definition of the sequence is

a_1=-3,, a_2=-7 and a_n=a_{n-2}-2a_{n-1}.

When n=3, we obtain;

a_3=a_{3-2}-2a_{3-1}.

\implies a_3=a_{1}-2a_{2}.

\implies a_3=-3-2(-7).

\implies a_3=11.

When n=4

\implies a_4=a_{2}-2a_{3}.

\implies a_4=-7-2(11)=-29.

When n=5

\implies a_5=a_{3}-2a_{4}.

\implies a_4=11-2(-29)=69.

Therefore the first five terms are;

-3,-7,11,-29,69

5 0
3 years ago
Help ASAP please I need the answers please please
max2010maxim [7]

Answer:

1 is adjacent and linear pair 2 is adjacent and not linear pair 3 is not adjacent and not linear pair

Step-by-step explanation:

4) angle 4and5 are adjacent

5)angle 1and4 are linear pair

6)angle 2and3 are linear pair

5 0
3 years ago
What do you know about a quadratic equation that has the following points (2, 0) and (10, 0)?
Agata [3.3K]

Answer:

C.  The x-coordinate of the vertex must be 6

Step-by-step explanation:

The parabola intercepts the x-axis when y = 0.

Therefore, if the quadratic equation has the points (2, 0) and (10, 0) then the x-intercepts or "zeros" are x = 2 and x = 10.

The x-coordinate of the vertex is the midpoint of the zeros.

\sf \implies midpoint=\dfrac{2+10}{2}=6

Therefore, the solution is option C.

<u>Additional Information</u>

The leading coefficient of a quadratic tells us if the parabola opens upwards or downwards:

  • Positive leading coefficient = parabola opens upwards
  • Negative leading coefficient = parabola opens downwards

We have not been given this information and so therefore cannot determine the way in which it opens.

As we do not know the way in which way the parabola opens, we cannot determine if the parabola will have a negative or positive y-intercept.

We have not been given the full quadratic equation, and so we cannot determine if the parabola is wider (or narrower) than the parent function.

3 0
2 years ago
Read 2 more answers
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