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Bumek [7]
4 years ago
6

Can someone plz help me !!!!!!!!

Mathematics
1 answer:
ASHA 777 [7]4 years ago
3 0
1.) It's a parallelogram
     area:
     3.5 x 5.8 = 20.3
     perimeter:
     4 + 4 + 5.8+5.8 = 19.6
2.)It's a right triangle 
<span>     area:
</span>    (6.92 x 11) ÷ 2 = 38.06
<span>    perimeter:
</span>    6.92 + 11 + 13 = 30.96
3.) ...that looks like a square tbh xD
<span>area:
</span>4.4 x 3 = 13.2
<span>perimeter:
</span>2.4
4.) Trapezoid 



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How do I show my work for solving the radius of a circle if the area is 78.5 cm^2
SIZIF [17.4K]

9514 1404 393

Answer:

  radius = 5 cm

Step-by-step explanation:

The point of "show your work" is to have to do exactly that. If you know the answer to the problem, you are being requested to show how you got it. If you got it by using a web calculator, then show your input and its result.

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If you worked the problem yourself, you probably did it by filling in numbers in the equation for the area of a circle:

  A = πr²

  78.5 = 3.14×r²

Dividing both sides by 3.14 gives the square of the radius:

  78.4/3.14 = r² = 25

Taking the positive square root gives the radius:

  r = √25 = 5

The area is in square centimeters, so the radius is in centimeters:

  radius = 5 cm

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3 years ago
You have come in contact with the Zombie Virus and are now infected with one strand. The
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Answer:

y=2^x

Step-by-step explanation:

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How can you find the side of a triangle only using angles 33 degrease, 49 degrees, and 98 degrees, and one side which is 100m. I
kumpel [21]

Answer:

72.17 m to the nearest hundredth.

Step-by-step explanation:

It is sin not cos.

We use the Sine Rule to do this

a / sin A = b / sin C = c / sin C.

Here we have:

100 / sin 49 =  x / sin 33

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3 0
3 years ago
Read 2 more answers
PLEASE HELP ME WITH THIS QUESTION ITS URGENT!!!
Alex Ar [27]

Start by distributing the exponent to each of the terms in (2u)^{3}.  This will become 2^{3} u^{3}, and 2^{3} =8.  Now, the expression is:

\frac{2u^{3} v^{2} }{8u^{3} * u^{2} }.


We can now simplify the bottom to read: 8u^{5} because when multiplying variables raised to an exponent, we add the exponents.  The expression now looks like:

\frac{2u^{3} v^{2} }{8u^{5} }


The 2/8 simplifies to 1/4:

\frac{u^{3} v^{2} }{4u^{5} }


Now, we have two u terms on the top and bottom.  When dividing variables raised to an exponent, we subtract the exponents.  However, since 3-5=-2, the term will be on the bottom to avoid the negative exponent.  The final answer is:

\frac{v^{2} }{4u^{2} }


Hope this makes sense!!


4 0
4 years ago
For each point identify the axis or quadrant where the point is located…
My name is Ann [436]

Answer:

quadrant ll

Step-by-step explanation:

A point on the y-axis will always have an x-coordinate of zero. Instructions: In the figure above, the point with coordinates (4,2) is located in quadrant I. The point with coordinates (-3,4) is located in quadrant II.

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