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skelet666 [1.2K]
3 years ago
12

What is 5d=470 and what is 8a=47

Mathematics
2 answers:
Igoryamba3 years ago
8 0
5d=470:

in this case we have to divide both sides by 5:

d=94

8a=47:

in this case we have to divide both sides by 8:

a=5.875

as a general rule, if you want to find out a value of a in
ab=c

you have to divide both sides of the equation by b (if it's not zero); then you will have left:

a=c/b

and if you calculate c/b, this will give you the answer


Gre4nikov [31]3 years ago
5 0
5d= 470 \\ \\ d=470:5 \\ \\ \boxed{\boxed{d= 94}} \\ \\ 8a=47 \\ \\ a=47:8 \\ \\ \boxed{\boxed{a=5.875}}
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kotykmax [81]

Answer:

10

Step-by-step explanation:

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3 years ago
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PLS HELP!!<br><br> What values of u and v make triangle XYZ = Triangle GFH
Katarina [22]

Answers:

u = 18

v = 20

========================================================

Work Shown:

The leg YZ is congruent to the left FH

This means YZ = FH and that leads to u+v-18 = 10u-8v

The hypotenuse ZX is congruent to the hypotenuse HG

This means ZX = HG and we get the equation 14v-14u+32 = v+u+22

----------------------

The system of equations we have so far is

u+v-18 = 10u-8v

14v-14u+32 = v+u+22

Let's get the equations into standard form

Start with the first equation

u+v-18 = 10u-8v

u+v = 10u-8v+18

u+v-10u+8v = 18

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-9(u-v) = 18

u-v = 18/(-9)

u-v = -2

Note how we can solve for the variable u to get

u = v-2

which we'll use later

----------------------

Let's get the other equation into standard form as well

14v-14u+32 = v+u+22

14v-14u-v-u = 22-32

-15u+13v = -10

Now plug in u = v-2 and solve for v

-15u+13v = -10

-15(v-2) + 13v = -10

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-2v+30 = -10

-2v = -10-30

-2v = -40

v = -40/(-2)

v = 20

Which means,

u = v-2

u = 20-2

u = 18

3 0
2 years ago
The length and width of a rectangle are measured as 31 cm and 28 cm, respectively, with an error in measurement of at most 0.1 c
MissTica

Answer:

\Delta A = 5.9\,cm^{2}

Step-by-step explanation:

The area of an rectangle is given by the following formula:

A = w\cdot h

Where:

w - Width, in centimeters.

h - Height, in centimeters.

The differential of the expression is derived hereafter:

\Delta A  = \frac{\partial A}{\partial w} \cdot \Delta w + \frac{\partial A}{\partial h}\cdot \Delta h

\Delta A = h \cdot \Delta w + w \cdot \Delta h

\Delta A = (31\,cm)\cdot (0.1\,cm) + (28\,cm)\cdot (0.1\,cm)

\Delta A = 5.9\,cm^{2}

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