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goldfiish [28.3K]
3 years ago
11

Plz help me asap u will get a new friend

Physics
1 answer:
emmainna [20.7K]3 years ago
7 0
2 is sedimentary and 3 is metamorphic
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Vector A has a magnitude of 50 units and points in the positive x direction. A second vector, B , has a magnitude of 120 units a
Alex Ar [27]

A) Vector A

The x-component of a vector can be found by using the formula

v_x = v cos \theta

where

v is the magnitude of the vector

\theta is the angle between the x-axis and the direction of the vector

- Vector A has a magnitude of 50 units along the positive x-direction, so \theta_A = 0^{\circ}. So its x-component is

A_x = A cos \theta_A = (50) cos 0^{\circ}=50

- Vector B has a magnitude of 120 units and the direction is \theta_B = -70^{\circ} (negative since it is below the x-axis), so the x-component is

B_x = B cos \theta_B = (120) cos (-70^{\circ})=41

So, vector A has the greater x component.

B) Vector B

Instead, the y-component of a vector can be found by using the formula

v_y = v sin \theta

Here we have

- Vector B has a magnitude of 50 units along the positive x-direction, so \theta_A = 0^{\circ}. So its y-component is

A_y = A sin \theta_A = (50) sin 0^{\circ}=0

- Vector B has a magnitude of 120 units and the direction is \theta_B = -70^{\circ}, so the y-component is

B_y = B sin \theta_B = (120) sin (-70^{\circ})=-112.7

where the negative sign means the direction is along negative y:

So, vector B has the greater y component.

8 0
3 years ago
A very long wire generates a magnetic field of 0.0020x 10^-4 T at a distance of 10 mm. What is the magnitude of the current? A)
zimovet [89]

Answer:

2*10^-<em>5</em>

Explanation:

<em>B=</em><em>I</em><em>L</em>

<em>I=</em><em>B</em><em>/</em><em>L</em>

<em>I=</em><em>0</em><em>.</em><em>0</em><em>0</em><em>2</em><em>0</em><em>*</em><em>1</em><em>0</em><em>^</em><em>-</em><em>4</em><em>/</em><em>1</em><em>0</em>

<em>I=</em><em>2</em><em>*</em><em>1</em><em>0</em><em>^</em><em>5</em>

6 0
3 years ago
A hot air balloon competition requires a balloonist to drop a ribbon onto a target on the ground. Initially the hot air balloon
Tpy6a [65]

Answer:

The answer is 3.48 seconds

Explanation:

The kinematic equation

y= y0+V0*t+1/2*a*(t*t)

-50=0+(0)t+1/2(-9.8)*(t*t)

t=3.194 seconds

During ribbons ball,

x=x0+ Vt+1/2*a*(t*t)

x= 0+(15)*(3.194)+1/2*(0)* (3.194*3.194)

x= 47.9157m

So, distance (D) = 100-47.9157= 52.084m

52.084m=0+15(t)+1/2*(0)(t*t)

t=52.084/15=3.472286= 3.48seconds

3 0
3 years ago
A 129-kg horizontal platform is a uniform disk of radius 1.51 m and can rotate about the vertical axis through its center. A 67.
blondinia [14]

Answer:

I = 274.75 kg-m²

Explanation:

given,

mass of horizontal platform = 129 Kg

radius of the disk = 1.51 m

mass of the person(m_p) = 67.5 Kg

standing at distance(r_p) = 1.09 m

mass of dog(m_d) = 25.3 Kg

sitting near the person(r_d) = 1.37 m from center

moment of inertia = ?

Moment of inertia of disc = \dfrac{1}{2}MR^2

Moment of inertia of the system

I = MOI\ of\ disk + m_p r_p^2 + m_d r_d^2

I = \dfrac{1}{2}MR^2 + m_p r_p^2 + m_d r_d^2

I = \dfrac{1}{2}\times 129 \times 1.51^2 + 67.5 \times 1.09^2 + 25.3\times 1.37^2

I = 274.75 kg-m²

3 0
3 years ago
A 14,700 N car is traveling at 25 m/s. The brakes are applied suddenly, and the car slides to a stop. The average braking force
Vlada [557]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

vo = 25 m/sec 
<span>vf = 0 m/sec </span>
<span>Fμ = 7100 N (Force due to friction) </span>
<span>Fg = 14700 N </span>
<span>With the force due to gravity, you can find the mass of the car: </span>
<span>F = ma </span>
<span>14700 N = m (9.8 m/sec²) </span>
<span>m = 1500 kg </span>
<span>Now, we can use the equation again to find the deacceleration due to friction: </span>
<span>F = ma </span>
<span>7100 N = (1500 kg) a </span>
<span>a = 4.73333333333 m/sec² </span>
<span>And now, we can use a velocity formula to find the distance traveled: </span>
<span>vf² = vo² + 2a∆d </span>
<span>0 = (25 m/sec)² + 2 (-4.73333333333 m/sec²) ∆d </span>
<span>0 = 625 m²/sec² + (-9.466666666667 m/sec²) ∆d </span>
<span>-625 m²/sec² = (-9.466666666667 m/sec²) ∆d </span>
<span>∆d = 66.0211267605634 m </span>
<span>∆d = 66.02 m</span>
7 0
3 years ago
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