<span>240,000 miles / hour²
Average acceleration can be calculated by dividing the change in speed by the elapsed time. Since the dragster's speed was 0 when the light turned green, the change in speed is simply 300 mph. Now, divide that by the time:
300 mph / 0.00125 hours = 240,000 miles / hour²
By the way, 0.00125 hours is just 4.5 seconds!</span>
Answer:
<h3>The answer is 16.67 m/s²</h3>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>16.67 m/s²</h3>
Hope this helps you
Answer:
0.558 atm
Explanation:
We must first consider that both gases behaves like ideal gases, so we can use the following formula: PV=nRT
Then, we should consider that, whithin a mixture of gases, the total pressure is the sum of the partial pressure of each gas:
P₀ = P₁ + P₂ + ....
P₀= total pressure
P₁=P₂= is the partial pressure of each gass
If we can consider that each gas is an ideal gas, then:
P₀= (nRT/V)₁ + (nRT/V)₂ +..
Considering the molecular mass of O₂:
M O₂= 32 g/mol
And also:
R= ideal gas constant= 0.082 Lt*atm/K*mol
T= 65°C=338 K
4.98 g O₂ = 0.156 moles O₂
V= 7.75 Lt
Then:
P°O₂=partial pressure of oxygen gas= (0.156x0.082x338)/7.75
P°O₂= 0.558 atm
Answer:
liquid.
Explanation:
That is almost the definition of a liquid. So the answer is a liquid.
Answer:
1404 N .
Explanation:
Force = rate of change of momentum
d/dt ( mv₁ - mv₂ )
If v₂ = - v₁
rate of change of momentum
= d/dt ( mv₁+mv₁ )
=2x v₁ dm / dt ( Here velocity of water v₁ throughout is constant )
Force = 2 xv₁ dm / dt
Given ,
v₁ = 18 m/s
dm / dt = rate of flow of mass of water
= 39 kg / s
Putting the values in the equation above
Force = 2xv₁ dm / dt
= 2x18 x 39
= 1404 N .
