Answer:
4.37 * 10^-4 J
Explanation:
Energy stored :
mgΔl / 2
m = mass = 10kg ; g = 9.8m/s² ; r = cross sectional Radius = 1cm = 1 * 10-2 m
Δl = mgl / πr²Y
Y = Youngs modulus = Y=3.5 ×10^10 ; l = Length = 1m
Δl = (10 * 9.8 * 1) / π * (1 * 10^-2)²* 3.5 ×10^10
Δl = 98 / 3.5 * π * 10^6
Δl = 0.00000891267
Energy stored :
mgΔl / 2
(10 * 9.8 * 0.00000891267) / 2
= 0.00043672083 J
4.37 * 10^-4 J
Answer: angular displacement in rad = 3038.45 rad
angular displacement in rev = 483.589 rev
Explanation: mathematically
Angular velocity = angular displacement / time taken.
Angular velocity = 33.5 rad/s, time taken = 90.7s
33.5 = angular displacement /90.7
Angular displacement = 33.5 * 90.7 = 3038.45 rad
But 1 rev =2π
Hence 3038.45 rad to rev is
3038.45/2π = 483.599 rev
Answer:
Q = 282,000 J
Explanation:
Given that,
The mass of liquid water, m = 125 g
Temperature, T = 100°C
The latent heat of vaporization, Hv = 2258 J/g.
We need to find the amount of heat needed to vaporize 125 g of liquid water. We can find it as follows :
or
Q = 282,000 J
So, the required heat is 282,000 J
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