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Lapatulllka [165]
3 years ago
10

Let f(x)=2x+2 and g(x)=x^2 State the domain of the operation: h(g(x))

Mathematics
1 answer:
faust18 [17]3 years ago
7 0

Answer: the domain of f(x)=2x+2 is all real numbers and the domain of g(x)=x^2 is (0, infinity)

Step-by-step explanation:

there is no horizontal asymptote given

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Hi, I have utterly no idea what I'm doing here.
Anna11 [10]

Answer:

Factored form: 2x(2x^2+x+1)

Step-by-step explanation:

You're subtracting them. :)

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What is the discounted price of a $500 cell phone with a discount of<br> 10% ?
iren2701 [21]
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2 years ago
If the area of the rectangle is 130 square inches then what is the rectangles height, h
fomenos

Answer:

130/l in where l is the length of the rectangle

Step-by-step explanation:

The formula for area of a rectangle is length by width where the width is the height of the rectangle

Given that area=130 in²

Lets assume the length of this rectangle is =l inches

Then ;

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5 0
3 years ago
x + 3y = 7 x - 3y = 1 Solve the system of equations. A) x = 4, y = 1 B) x = 1, y = 4 C) x = - 2 3 , y = 3 D) x = 3, y = - 2 3
Alik [6]
X+3y=7
x-3y=1
add them together

x+3y=7
<u>x-3y=1 +
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subsitute
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x=4
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answer is A
<u />
6 0
3 years ago
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Without actual division prove that x4 +2x3 -2x2 +2x -3 is exactly divisible by<br> x2 +2x-3
Brut [27]

Answer:

Step-by-step explanation:                

\displaystyle\Large\boldsymbol{} x^4+2x^3-2x^2+2x-3= \\\\\\x^4+2x^2(x-1)+2x-\underbrace{2-1}_{-3}=  \\\\\\x^4-1+2x^2(x-1)+2x-2 = \\\\\\(x^2-1)(x^2+1)+2x^2(x-1)+2(x-1) = \\\\\\\underline{(x-1)}(x+1)(x^2+1)+2x^2\underline{(x-1)} +2\underline{(x-1)} =\\\\\\(x-1)((x+1)(x^2+1)+2x^2+2)=\\\\\\(x-1)(x^3+x^2+2x^2+x+2+1)=\\\\\\(x-1)(x^3+3x^2+x+3) =\\\\\\(x-1)( \underline{(x+3)}x^2+\underline{(x+3)})=(x^2+1)\underbrace{(x-1)(x+3)}_{x^2+2x-3}= \\\\\\(x^2+1)(x^2+2x-3) : (x^2+2x-3)=x^2+1

7 0
2 years ago
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