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blondinia [14]
3 years ago
5

What is the expand form for 0.632

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0
0.600 is ur answer Hopes this helps u.
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What is the sum of the areas of circle C and circle D?
Galina-37 [17]
141 units is the answer.
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3 years ago
WHAT IS THE ANSWER ?? PLEASE HELP !!
Jlenok [28]

Answer:

B. 43°

Step-by-step explanation:

Internal angles of the triangle are:

  • 180°-90°=90° and
  • 180°-133°= 47°

So It is a right triangle and the missing angle is:

  • p= 90°- 47°= 43°
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3 years ago
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Land's Bend sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the intern
nata0808 [166]

Answer:

−35.713332 ; 0.313332

Step-by-step explanation:

Given that:

Sample size, n1 = 11

Sample mean, x1 = 79

Standard deviation, s1 = 18.25

Sample size, n2 = 18

Sample mean, x2 = 96.70

Standard deviation, s2 = 20.25

df = n1 + n2 - 2 ; 11 + 18 - 2 = 27

Tcritical = T0.01, 27 = 2.473

S = sqrt[(s1²/n1) + (s2²/n2)]

S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]

S = 7.284

(μ1 - μ2) = (x1 - x2) ± Tcritical * S

(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284

(μ1 - μ2) = - 17.7 ± 18.013332

-17.7 - 18.013332 ; - 17.7 + 18.013332

−35.713332 ; 0.313332

3 0
3 years ago
What are the parent function in transformation​
mylen [45]

Answer:

The transformation of the parent function is shown in blue. It is a shift down (or vertical translation down) of 1 unit. A reflection on the x-axis is made on a function by multiplying the parent function by a negative.

Step-by-step explanation:

6 0
4 years ago
A patient is given a solution containing 0.625 g of calcium carbonate. If the calcium carbonate solution contains 1250 mg per 5
Dmitrij [34]

Answer: 2.5 mL

Step-by-step explanation:

Given : A patient is given a solution containing 0.625 g of calcium carbonate.

i.e. Patient required calcium carbonate = 625 mg  [∵ 1 g = 1000 mg]

Let x be the amount of solution ( in millimeters) given to the patients.

Ratio of amount of calcium carbonate (mg) to amount of solution (ml) =\dfrac{625}{x}

If the calcium carbonate solution contains 1250 mg per 5 mL,

Then, Ratio of amount of calcium carbonate to amount of solution =\dfrac{1250}{5}

By using proportion we have :-

\dfrac{625}{x}=\dfrac{1250}{5}\\\\\Rightarropw\ x=\dfrac{5\times625}{1250}=2.5

Hence, 2.5 mL solution were given to the patient.

3 0
3 years ago
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