WOULD APPRECIATE SOME HELP 20 POINTS :)

Is one side of a rectangular fish tank best represented by a point, line, plane, or ray?

Inessa05 [86]

<span>One side of a rectangular fish tank can be best represented by a plane because it is two dimensional.Whereas,point,line or a ray are all one dimensional and hence they cannot represent a rectangle as it has two dimensions.</span>

6 0

3 years ago

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I need help :) please and thank u if u get it right i will give u brainlist

Dvinal [7]

Answer:

4 14/25

Step-by-step explanation:

4.56 = 4 56/100 = 4 14/25

6 0

2 years ago

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Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago

Hitung jarak di antara titik P(7, 1) dengan titik Q(7, 8)

MaRussiya [10]

Answer:

7 units

Step-by-step explanation:

Distance between 2 points

= $\sqrt{(y1 - y2)^{2} + (x1 - x2) {}^{2} }$

Thus, distance PQ

$=\sqrt{(8 - 1)^{2} + (7 - 7)^{2} } \\ = \sqrt{7^{2} } \\ = 7$

Or you could simply take 8-1= 7 since both points have the same x-coordinate. Thus, PQ is a vertical line and the distance between them is due to the difference in their y-coordinate.

5 0

3 years ago

Please help i'll mark brainliest if your answer is correct

amid [387]

Split the shape in 3 rectangles
4x2=8x2= 16 ( the bottom and top rectangle)
6x2= 12 (middle rectangle)
16+12=28

6 0

3 years ago