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3 years ago

{d(1)=13 {d(n)=d(n−1)+17 Find the 4 term in the sequence

Mathematics

1 answer:

pickupchik [31]3 years ago

3 0

d(4) = 64

Step-by-step explanation:

Step 1:

d(n)=d(n−1)+17 

d(2) = d(1) +17

= 13+17

= 30

d(3) = d(2) + 17

= 30+17

=47

Step 2:

d(4) = d(3) + 17

= 47+17

= 64

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3 years ago

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yaroslaw [1]

Answer:

Option (A).

Step-by-step explanation:

$8\frac{4}{5}$ is a mixed fraction and can be written as,

$8\frac{4}{5}=8+\frac{4}{5}$ [Combination of a whole number and a fraction]

When we multiply this mixed fraction by 7,

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$=(7\times 8)+(7\times \frac{4}{5})$ [Distributive property → a(b + c) = a×b + a×c]

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7 0

3 years ago

If y is directly proportional to x squared and y = 3 when x = 2, what is y when x = 8?

Anestetic [448]

Answer:

y = 63

Step-by-step explanation:

y is directly proportional to x²

As given,

when y = 3 => x = 2

So, 3 = 4 - 1

Which means the relation can be written as :-

y = x² - 1

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y = (8)² - 1

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2 years ago

Read 2 more answers

find the measure of the arc or angle indicated. assume that lines which appear to be diameters are actual diameters just enter t

konstantin123 [22]

Answer:

I think D

if wrong correct me plssssssss

have a nice day

And good luck if you have exam

#Captainpower

8 0

3 years ago

Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2

Ipatiy [6.2K]

Answer:

$\frac{dAB}{dt}=340 mil/h$

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:

$AB^{2} =AO^{2}+BO^{2}$ (1)

$AB =\sqrt{AO^{2}+BO^{2}}=$

$AB =\sqrt{90^{2}+120^{2}}=150 miles$

If we take the derivative of the equation (1) we could find the change of the distance between planes.

$2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}$

$2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h$

$\frac{dAB}{dt}=\frac{102000}{150*2}$

Finally,

$\frac{dAB}{dt}=340 mil/h$

I hope it helps you!

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3 years ago

{d(1)=13 {d(n)=d(n−1)+17 ​ Find the 4 term in the sequence

{d(1)=13 {d(n)=d(n−1)+17 Find the 4 term in the sequence