What is the inverse of f(x) = one-thirdx + 2? h(x) = one-thirdx + 2 h(x) = one-thirdx - 2 h(x) = 3x - 2 h(x) = 3x - 6
2 answers:
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Answer:
Step-by-step explanation:
The average value theorem sets:
if f (x) is continuous in [a, b] and derivable in (a, b) there is a c Є (a, b) such that
, where
f(a)=f(π/2)=-4*sin(π/2) = -4*1= -4
f(b)=(3π/2)=-4*sin(3π/2) = -4*-1 = 4
⇒
c≅130