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svp [43]
3 years ago
13

A group of college students are going to a lake house for the weekend and plan on renting small cars and large cars to make the

trip. Each small car can hold 5 people and each large car can hold 8 people. A total of 5 cars were rented which can hold 34 people altogether. Determine the number of small cars rented and the number of large cars rented.
Mathematics
1 answer:
DedPeter [7]3 years ago
7 0

Answer:

  2 small; 3 large

Step-by-step explanation:

Using s and L for the number of small and large cars, respectively, we have ...

  5s +8L = 34 . . . . number of passengers

  s + L = 5 . . . . . . . number of cars

  5s +8(5 -s) = 34 . . . . substitute for L

  -3s +40 = 34

  -3s = -6 . . . . . . subtract 40

  s = 2 . . . . . . . . divide by -2

  L = 5-2 = 3

2 small cars and 3 large cars were rented.

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Answer:

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Answer:

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Step-by-step explanation:

a) sin(α)/a = sin(β)/b

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sin(41°)/BD = sin(55°)/13.4

BD = 13.4*sin(41°)/sin(55°) = 10.73 cm ≈ 10.7 cm

b) From ΔBCD , ∠BDC = 180-(41+55) = 84°

∠ABD and ∠BDC are alternate interior angles, so they are congruent, and

∠ABD = ∠BDC  = 84°

AD²= AB² + BD² - 2*AB*BD*cos (∠ABD) =

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AD =√(133.93) ≈11.6 cm

c) Area(ADB) = (1/2)*AB*BD*sin(∠ABD)=(1/2)*5.6*10.73*sin(84°) ≈ 29.9 cm²

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