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Rina8888 [55]
4 years ago
12

How many pounds is a quarter ton??

Mathematics
1 answer:
Valentin [98]4 years ago
6 0
551.155655 pounds are in a quarter ton.
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Does someone want to help me solve this problem
Hoochie [10]

Answer:

(cx)2-(dy) 2

Step-by-step explanation:

Formula a2-b2= (a+b) (a-b)

By given formula

(cx)2 - (dy) 2 = (cx+dy) (cx-dy)

3 0
3 years ago
What is the arithmetic sequence in this problem . help plz
adell [148]

Answer:

<u>a(n)=80*(9/10)^(n-1)</u>

Step-by-step explanation:

I think u r confused

this sequence is geometric not arithmetic

HOw we know that ??

when we get a common difference  <u>that must Be equal  </u>

d=72-80=-8  not equal to  d=64.8-72=-7.2

So it is not arithmetic

but when we get the common ratio that also must <u>be equal </u>

r=72/80=9/10 equal to   r=64.8/72=9/10

So it is geometric

By using this equation:

a(n)=a*r^(n-1)

and we have <u>a=80 , r=9/10</u>

Then       <u>a(n)=80*(9/10)^(n-1)</u>

<em>I really hope this helps <3</em>

6 0
3 years ago
Tia measured the daily high temperature in Kats, Colorado for each of the 30 days in April. She then created both a dot plot and
lara31 [8.8K]

*see attachment below showing the dot plot and box plot created by Tia

Answer:

Dot plot

Step-by-step explanation:

In a dot plot, the temperature of a day is represented by 1 dot. There are 30 dots on the box plot shown in the attachment that was made by Tia.

This dot plot display makes it easier to find how many days had a temperature that is higher than 15°.

Thus, from the dot plot, we have:

2 dots representing 2 days having a temperature of 16°C each

2 days also have daily temperature of 17°C

2 days have temperature of 18°C as well, and

1 day has temperature of 19° C.

Therefore, the number of days that had a temperature above 15°C is 7 days.

3 0
3 years ago
Read 2 more answers
Find a function ω(x) such that the function f(x) = sin(ω(x)) has the roots at π, π2
atroni [7]

So, I came up with something like this. I didn't find the final equation algebraically, but simply "figured it out". And I'm not sure how much "correct" this solution is, but it seems to work.

f(x)=\sin(\omega(x))\\\\f(\pi^n)=\sin(\omega(\pi^n))=0, n\in\mathbb{N}\\\\\\\sin x=0 \implies x=k\pi,k\in\mathbb{Z}\\\Downarrow\\\omega(\pi^n)=k\pi\\\\\boxed{\omega(x)=k\sqrt[\log_{\pi} x]{x},k\in\mathbb{Z}}

8 0
3 years ago
Which ratio is not equivalent to 5/3
Kazeer [188]

4/3 I hope this helps

7 0
4 years ago
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