Answer:
This task would be especially well-suited for instructional purposes. Students will benefit from a class discussion about the slope, y-intercept, x-intercept, and implications of the restricted domain for interpreting more precisely what the equation is modeling.
One potential confusion students may have follows from the subtle difference between what the car is doing and the idea of slope as the ratio between the change in vertical distance on the graph and the change in horizontal distance on the graph. Because the car is traveling one mile on a down-hill slope, the situation could be represented as a right triangle with a hypotenuse of 5,280 ft and a leg of 250 ft; using the Pythagorean Theorem they would find that the other leg is approximately 5,274 ft. Following through on this interpretation, a student might conclude that the car travels a horizontal distance of approximately 5,274 ft for every 250 ft in vertical distance and arrive at a slope of approximately -0.047. While this is, in some sense, the slope of the hill, it is not the slope of the function as described. This interpretation yields numbers that are very close to the situation described in the task, yet conceptually different since the distance traveled by the car would now be expressed in terms of horizontal distance traveled as opposed to distance along the slope of the hill to compute the elevation. If students do indeed pursue this line of reasoning, the task provides an opportunity to compare and contrast the graph of the function and what it represents with a drawing of the hill and the vertical and horizontal distances traversed with each mile down the slope.
Step-by-step explanation:
Given:
Uniform distribution of length of classes between 45.0 to 55.0 minutes.
To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:
45+55/2 = 50
So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />
Answer :
It is D because you have to subtract 4.73 from both sides in order to isolate the y by itself and get the answer which is 3.27
Step-by-step explanation:
If the two lengths are 7 and 3, then I believe the length of the hypotenuse would be approximately 7.62.
Answer:
Pretty sure 25%.
Step-by-step explanation:
First, you would need to see how many times 60 goes into 100, because a percent is ALWAYS over 100. You should get an answer of 1.66666667. Then you if you multiply it to one of the numbers then you have to do it to the other number. So, you would do 15 times 1.66666667. You would get 25. So, that would be 25 over 100 or 25/100. And 25 over 100 is 25%.
I hope I helped! :) Sorry if it's wrong :(
