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3 years ago

Help plzzzz I need help

Mathematics

1 answer:

yan [13]3 years ago

8 0

Answer:

1. 425,328 -> 425,330

2. 105,025 -> 105,030

3. 45,527 -> 45,530

4. 35,478 -> 35,480

5. 212,369 -> 212,370

Step-by-step explanation:

000,0<u>0</u>0 the underlined number is the tens place. In order for the tens place to round up the ones place must be 5 or above. If the ones place is lower than 5 you round down to the nearest tens.

In Example:

333,389 you would round up to 333,390 because of the 9 in the ones place.

Now, 333,333 you would round down to 333,330 because of the 3 in the ones place

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Assume the hold time of callers to a cable company is normally distributed with a mean of 5.5 minutes and a standard deviation o

Ierofanga [76]

Answer:

The percent of callers are 37.21 who are on hold.

Step-by-step explanation:

Given:

A normally distributed data.

Mean of the data, $\mu$ = 5.5 mins

Standard deviation, $\sigma$ = 0.4 mins

We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.

Lets find z-score on each raw score.

⇒ $z_1=\frac{x_1-\mu}{\sigma}$ ...raw score, $x_1$ = $5.4$

⇒ Plugging the values.

⇒ $z_1=\frac{5.4-5.5}{0.4}$

⇒ $z_1=-0.25$

For raw score 5.5 the z score is.

⇒ $z_2=\frac{5.8-5.5}{0.4}$

⇒ $z_2=0.75$

Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.

We have to work with P(5.4<z<5.8).

⇒ $P(5.4$

⇒ $P(-0.25$

⇒ $P(z$

⇒ $z(1.5)=0.7734$ and $z(-0.25)=0.4013$ .<em>..from z -score table.</em>

⇒ $0.7734-0.4013$

⇒ $0.3721$

To find the percentage we have to multiply with 100.

⇒ $0.3721\times 100$

⇒ $37.21$ %

The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21

4 0

3 years ago

Tom's toy box is shown below. The toy box is shaped like a rectangular prism. It has 5 wooden faces and is open on the top. What

mihalych1998 [28]

Answer:

1100 square inches

Step-by-step explanation:

The faces are all rectangles (area = length x width)

Area of bottom: 20 x 10 = 200

Area of front: 20 x 15 = 300

Area of back (same as front) = 300

Area of right side: 10 x 15 = 150

Area of left side (same as right side) = 150

Total of all the sides: 1100

8 0

3 years ago

A circle is circumscribed around a square and another circle is inscribed in the square. If the area of the square is 9 in2, wha

lesantik [10]

Answer:

√2:1

Step-by-step explanation:

First we need to know that the length of the side of the square is equal to the diameter of the inscribed circle i.e

L = di

Given the area of the square to be 9in², we can get the length of the square.

Area of a square = L²

L is the length of the square.

9 = L²

L = √9

L = 3in

Hence the length of one side of the square is 3in

This means that the diameter of the inscribed circle di is also 3in.

Circumference of a circle = π×diameter of the circle(di)

Circumference of inscribed circle = π×3

= 3π in

For the circumscribed circumscribed circle, diameter of the outer circle will be equivalent to the diagonal of the square.

To get the diagonal d0, we will apply the Pythagoras theorem.

d0² = L²+L²

d0² = 3²+3²

d0² = 9+9

d0² = 18

d0 = √18

d0 = √9×√2

d0 = 3√2 in

Hence the diameter of the circumscribed circle (d0) is 3√2 in

Circumference of the circumscribed circle = πd0

= π(3√2)

= 3√2 π in

Hence, ratio of the circumference of the circumscribed circle to the one of the inscribed will be 3√2 π/3π = √2:1

8 0

3 years ago

Find the missing side length.

Dmitry [639]

Answer:

4 cm, if you subtract 9 from 13 you get four.

8 0

3 years ago

The machinist's goal was to increase his production by at least 10% each day. Assume he achieved his goal. If he was able to mac

quester [9]

25+10%= 27.5 Hope this helps.

8 0

3 years ago

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