Question

The area of a rectangle is 63m squared,and the length of the rectangle is 5 m more than twice the width.Find the dimensions of the rectangle

Answer 1

Given:
Area(A)= 63m^2
Length (L)= 2W+5
Width (W)=?

A=LxW
63=(2W+5)(W)
63=2W^2 + 5W
0=2W^2+5W-63
0=(2W-9)(W+7)
2W-9=0 then W=4.5 and W+7=0 then W=-7
Can only use 4.5 since it is positive and distance is positive.
W= 4.5 m
L=2W+5=2 (4.5)+5=9+5=14m