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finlep [7]
3 years ago
10

A sculptor has just finished creating a large wooden sphere for a sculpture he is working on. The sphere has a radius of 4.3 fee

t and weighs approximately 10,578.59 pounds. What is the approximate density of the wood used to create the sphere? I need help
Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0
Density = mass/volume

the mass is 10578.9 pounds

the volume of a sphere is v = 4/3 πr^3

v = (4/3) (π) (4.3)^3
v = 333.04

10578.9 / 333.04 = 31.76

the final density is 31.76!!
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Step-by-step explanation:

5.

12,\:30\\\\\mathrm{Prime\:factorization\:of\:}12:\quad 2\times\:2\times\:3\\\mathrm{Prime\:factorization\:of\:}30:\quad 2\times\:3\times\:5\\\\=2\times\:2\times\:3\times\:5\\\\=60

6.

6,\:10\\\\\mathrm{Prime\:factorization\:of\:}6:\quad 2\times\:3\\\mathrm{Prime\:factorization\:of\:}10:\quad 2\times \:5\\\\=2\times \:3\times \:5\\\\=30

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16,\:24\\\\\mathrm{Prime\:factorization\:of\:}16:\quad 2\times \:2\times\:2\times\:2\\\mathrm{Prime\:factorization\:of\:}24:\quad 2\times\:2\times\:2\times\:3\\\\=2\times\:2\times\:2\times\:2\times\:3\\\\=48

8.

14,21\\\\\mathrm{Prime\:factorization\:of\:}14:\quad 2\times\:7\\\mathrm{Prime\:factorization\:of\:}21:\quad 3\times\:7\\\\=2\times\:7\times\:3\\\\=42

9.

9,15\\\\\mathrm{Prime\:factorization\:of\:}9:\quad 3\times\:3\\\mathrm{Prime\:factorization\:of\:}15:\quad 3\times\:5\\\\=3\times\:3\times\:5\\\\=45

10.

5,\:11\\\\\mathrm{Prime\:factorization\:of\:}5:\quad 5\\\mathrm{Prime\:factorization\:of\:}11:\quad 11\\\\=5\times \:11\\\\=55

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3 years ago
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