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Arlecino [84]
3 years ago
6

Word problem.. i need help. Due at midnight

Mathematics
1 answer:
aniked [119]3 years ago
8 0

The Brady family received 1 letter on July 28.

Step-by-step explanation:

Step 1:

Assume a = the number of letters, b = the number of bills, c = the number of ads, and d = the number of magazines.

From the question, they got 15 pieces of mail that day so a+b+c+d=15.

They got 5 more magazines than bills so d = b + 5.

The got the same number of letters as ads so a=c.

They got 3 more bills than ads so b= c + 3.

Step 2:

As we have only one equation to solve the values, we need to make every term in terms of a single term.

We make everything in terms of c.

So a=c, b = c+3, c=c, d = b+5 = (c+3)+5=c+8.

Substituting all this in the equation, we get

a + b+c+d =(c)+(c+3)+(c)+(c+8) = 15, 4c+11=15.

4c=4, c = 1.

Step 3:

Substituting c = 1 in other terms, we get

a=c=1,

b=c+3=1+3=4,

c=1, and

d = c+8 = 1+8=9.

As a = 1, they received 1 letter that day.

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The U.S. Department of Agriculture records data on farm acreage and number of farms by county for every county in the country. T
lisabon 2012 [21]

Solution :

From the table,

Number of countries = $N_i$

Mean = $\overline Y_i$

Standard deviation = $\sigma_i$

Margin of error of B = 50,000 acres

So we determine the $\text{sample size n}$ and then allocate the four regions of $n_1, n_2, n_3$ and $n_4$.

Under the $\text{proportional allocation}$, the $\text{equation}$ for the value of $n_1$ which yields $V(\overline Y_{st}) = D = \frac{B^2}{H}$  is given by :

$n=\frac{\sum_{K=1}^L N_K \sigma^2_K}{ND+\frac{1}{N}\sum_{K=1}^L N_K \sigma^2_K}$

Let us complete the numerator

$\sum_{K=1}^L N_K \sigma^2_K = N_1\sigma_1^2 + N_2\sigma_2^2 + N_3\sigma_3^2 + N_4\sigma_4^2$

                $= 1052 \times (271)^2 +  210 \times (79)^2 + 1376 \times (244)^2 + 418 \times (837)^2 $

                = 453329920

The bound on the error of estimation is B = 50,000 acres

Hence we get

$D=\frac{B^2}{H}$

  $=\frac{50000^2}{4}$

  = 625,000,000

$n=\frac{\sum_{K=1}^L N_K \sigma^2_K}{ND+\frac{1}{N}\sum_{K=1}^L N_K \sigma^2_K}$

  $=\frac{453329920}{3056 \times 625 + \frac{1}{3056} \times 453329920}$

 = 220.24044

≈ 221 (approximately)

Therefore, the sample size under the proportional allocation from each stratum are given by :

$n_1=n\left[\frac{N_1}{\sum_{K=1}^\mu N_K}\right]$

   $=221\left[\frac{1052}{3056}\right]$

   ≈ 76

$n_2=n\left[\frac{N_2}{\sum_{K=1}^\mu N_K}\right]$

   $=221\left[\frac{210}{3056}\right]$

   ≈ 15

$n_3=n\left[\frac{N_3}{\sum_{K=1}^\mu N_K}\right]$

   $=221\left[\frac{1376}{3056}\right]$

   ≈ 100

$n_4=n\left[\frac{N_4}{\sum_{K=1}^\mu N_K}\right]$

   $=221\left[\frac{418}{3056}\right]$

   ≈ 30

Thus, we should select 76 counties from North central region, 15 counties from the north east region, 100 from south region and 30 from west region.

We can also estimate mean acreage of each county across all the county with a margin of error of 50,000 acres.

8 0
3 years ago
What can be concluded about the spread of the histogram? A histogram titled Maria's Monthly Jogging has miles run on the x-axis
Rainbow [258]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
I need help asap :):):):
Kamila [148]

Answer:

its the second one

Step-by-step explanation:

6 0
3 years ago
https://lists.office.com/Images/2fce1dfb-919f-4938-aab8-c47f0fc9182d/759a6d77-ea1a-4b50-a9bc-86157c96a662/T14LEZ48DGIIWGRBN9LPBU
Darina [25.2K]

Answer:

54 is th area

Step-by-step explanation:

i have a pitucre your welcome :)

7 0
3 years ago
A tree is 58 inches tall. how tall is it in feet and inches
mart [117]
A foot is 12 inches.
12 can go into 58 evenly 4 times, since 12• 4 equals 48 but 12 • 5 equals 60. This means that the tree is at least 4 feet. Then to find the leftover inches we do 58-48 equals 10, therefore the answer is 58 inches translates to 4 feet and 10 inches.
8 0
3 years ago
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