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3 years ago

15

State the x- and y-intercepts of each equationy =

a1" title="\frac{3}{4}" alt="\frac{3}{4}" align="absmiddle" class="latex-formula">x + 3

1 answer:

Jet001 [13]3 years ago

5 0

Answer:

yintercept: (0,3) or 3

x intercept: (-4,0) or -4

Step-by-step explanation:

The y intercept is what you get when x=0

.75*0+3

3

The x intercept is what you get when y=0

0=.75x+3

-3=.75x

-4=x

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The equation y=0.002x-0.20 can be used to determine the approximate profit,y in dollars,of producing x items.solve for x. How ma

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Answer:

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Step-by-step explanation:

from the equation y = 0.002x -0.20

where y is the profit in dollars

and x is the number of items

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will be by substituting $3933 for y in the equation and solving for x,

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3 years ago

Read 2 more answers

Conduct the appropriate hypothesis test and compute the test statistic. A company that produces fishing line undergoes random te

andre [41]

Answer:

Option D) Yes, because the test statistic is -2.01

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 30 pound

Sample mean, $\bar{x}$ = 29.1 pounds

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = 2 pounds

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 30\text{ pounds}\\H_A: \mu < 30\text{ pounds}$

We use one-tailed(left) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{29.1 - 30}{\frac{2}{\sqrt{20}} } = -2.012$

Now,

$t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = -1.729$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis. Thus, there were enough evidence to conclude that the fishing line breaks with an average force of less than 30 pounds.

Option D) Yes, because the test statistic is -2.01

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3 years ago