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UkoKoshka [18]
3 years ago
7

Jim had some dimes, quarters, and nickels. First, he counted only the dimes and quarters and found that he had 9 coins. Then, he

counted only the nickels and dimes and found there were 10 coins. He saw that he had 15 coins altogether. How much money does Jim have? Answer in dollars and cents.
Mathematics
1 answer:
Olegator [25]3 years ago
7 0

Answer:

$1.90

Step-by-step explanation:

Represent the numbers of nickels, dimes and quarters by n, d and q.

Then: d + q = 9, or q = 9 - d.

Also, n + d = 10

Lastly, n + d + q = 15.

Let's substitute 9 - d for q in the equation immediately above:

n + d + (9 - d) = 15, or n + 9 = 15.  Then n must be 6.

In summary, Jim has 6 nickels, (10 - 6) dimes and (9 - 4) quarters, or:

                                    6 nickels, 4 dimes and 5 quarters

Thus, he has 5($0.05) + 4($0.10) + 5($0.25), or

                         $0.25   +   $0.40   + $1.25, or          $1.90

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List all possible rational roots. Then use synthetic division to confirm which rational roots exist:
Kisachek [45]

Answer:

\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term  and q is a factor of the leading coefficient.

\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

In your function, the constant term is -10 and the leading coefficient is 2, so

\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0
4 years ago
Solve using the Pythagorean theorem.<br>need urgent help​
Olin [163]

Answer:

y = 7

Step-by-step explanation:

Mathematically, according to the Pythagoras’ theorem;

The square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the two other sides

The hypotenuse is the side that faces the right angle and it is represented by the square root of 85 here

Thus, we have it that;

(√85 )^2= 6^2 + y^2

85 = 36 + y^2

y^2 = 85-36

y^2 = 49

y = √49

y = 7

3 0
3 years ago
-7(4-6) - 9<br> Please can someone help me!
Pepsi [2]

Answer:

5

Step-by-step explanation:

-7 x 4 = -28

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3 years ago
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Rom4ik [11]

Answer:

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x/0.7 = 21

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8 0
3 years ago
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BRAINLIEST HELP.............
Rus_ich [418]

I think the answer should be b, since y=3 when x=0, according to the option B.

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