The basics would be that you'd need to find out if they could exchange genetic information. If not, they couldn't be considered part of one species. Set-up 2 artificial environments so both groups would produce pollen at the same time. Fertilise both plants with the other's pollen. Then fertilise the plants with pollen from their own group.
Count the number of offspring each plant produces.
If the plants which were fertilised by the opposite group produce offspring, they are of the same species. You can then take this further if they are of the same species by analysing if there is any difference between the number (and health) of offspring produced by the crossed progeny and by the pure progeny. You'd have to take into account that some of them would want to grow at different times, so a study of the progeny from their first sprout until death (whilst emulating the seasons in your ideal controlled environment). Their success could then be compared to that of the pure-bred individuals.
Make sure to repeat this a few times, or have a number of plants to make sure your results are accurate.
Or if you couldn't do the controlled environment thing, just keep some pollen one year and use it to fertilise the other group.
I'd also put a hypothesis in there somewhere too.
The independent variable would be the number of plants pollinated. The dependant variable would be the number of progeny (offspring) produced.
Answer:
Im doing this but I was honestly looking for a cheat sheet lol
Answer:
Yellow smooth - 9
Yellow wrinkle - 3
Green smooth- 3
Green Wrinkle - 1
Explanation:
Let the green color of the seed be depicted by "G" and the yellow color of the seed be depicted by "g"
Let the smooth the seed be depicted by "R" and wrinkled seed be depicted by "r"
F1 cross -
true breeding smooth green plant ( RRGG) and true breeding wrinkled yellow (rrgg)
F1 gamete will be RG, RG, rg, rg
F1 offspring will be RrGg , Thus all F1 offspring will be heterozygous smooth and yellow.
Thus, R is dominant over r and g is dominant over G
F2 Generation –
RrGg x RrGg
Gametes will be RG, Rg, rG, rg
RG Rg rG rg
RG RRGG RRGg RrGG RrGg
Rg RRGg RRgg RrGg Rrgg
rG RrGG RrGg rrGG rrGg
rg RrGg Rrgg rrGg rrgg
R is dominant over r and g is dominant over G
Genotypes are –
RRGG - 1 (Smooth Green)
RRGg-2 (Smooth yellow)
RrGG-2 (Smooth Green)
RrGg-4 (Smooth yellow)
RRgg- 1 (smooth yellow)
Rrgg – 2 (Smooth yellow)
rrGG – 1 (wrinkled Green)
rrGg – 2 (Wrinkled yellow)
rrgg – 1 (wrinkled yellow)
Yellow smooth - 9
Yellow wrinkle - 3
Green smooth- 3
Green Wrinkle - 1
First one, disease causing microorganisms
