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finlep [7]
3 years ago
7

At a concession stand, seven hot dog (s )and two hamburger (s )cost $16.75; two hot dog (s )and seven hamburger (s )cost $19.25.

Find the cost of one hot dog and the cost of one hamburger.
Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0

One hot dog costs $1.75 and one hamburger costs $2.25

Step-by-step explanation:

Let,

Hot dog = x

Hamburger = y

According to given statement;

7x+2y=16.75   Eqn 1

2x+7y=19.25   Eqn 2

Multiplying Eqn 1 by 2;

2(7x+2y=16.75)\\14x+4y=33.50\ \ \ Eqn\ 3

Multiplying Eqn 2 by 7;

7(2x+7y=19.25)\\14x+49y=134.75\ \ \ Eqn\ 4

Subtracting Eqn 3 from Eqn 4;

(14x+49y)-(14x+4y)=134.75-33.50\\14x+49y-14x-4y=101.25\\45y=101.25

Dividing both sides by 45;

\frac{45y}{45}=\frac{101.25}{45}\\y=2.25

Putting y=2.25 in Eqn 1

7x+2(2.25)=16.75\\7x+4.50=16.75\\7x=16.75-4.50\\7x=12.25

Dividing both sides by 7;

\frac{7x}{7}=\frac{12.25}{7}\\x=1.75

One hot dog costs $1.75 and one hamburger costs $2.25

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/2479097
  • brainly.com/question/2480897

#LearnwithBrainly

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