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2 years ago

Im about to cry please help

Mathematics

2 answers:

Dovator [93]2 years ago

7 0

Answer: i'm going to sound real stup!d but i think it's B

Step-by-step explanation:

enot [183]2 years ago

4 0

Answer:

Try D

Step-by-step explanation:

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The amount of time t it takes for a group of volunteers to clean up a park varies inversely with the number of volunteers v. If

sweet-ann [11.9K]

T ∝ 1/v

so, t = k/v or tv = k 

Then, with t = 2.5 and v = 5 we have: 

2.5 = k/5 

so, k = 12.5 

Therefore, t = 12.5/v or vt = 12.5 HOPE IT HELPED

4 0

3 years ago

Read 2 more answers

Find the area of the region under the graph of f on [a, b]. f(x) = x2 − 8x + 17; [−1, 2]

Harman [31]

Answer:

The area is 42 area units.

Step-by-step explanation:

The area of a function f(x) on an interval [a,b] is given by:

$A = \int\limits^a_b {f(x)} \, dx$

Applying to this question:

$A = \int\limits^-1_2 {x^2 - 8x + 17} \, dx$

Then

$F(x) = \frac{x^{3}}{3} - 4x^{2} + 17x$

$A = F(2) - F(-1)$

$F(2) = frac{2^{3}}{3} - 4*2^{2} + 17*2 = \frac{8}{3} + 18 = \frac{8 + 3*18}{3} = \frac{62}[3}$

$F(-1) = frac{(-1)^{3}}{3} - 4*(-1)^{2} + 17*(-1) = -\frac{1}{3} - 21 = \frac{-1 - 21*3}{3} = -\frac{64}[3}$

$A = F(2) - F(-1) = \frac{62}[3} - (-\frac{64}[3}) = \frac{62+64}{3} = 42$

The area is 42 area units.

5 0

3 years ago

Rachael got a 550 on the analytical portion of the Graduate Record Exam (GRE). If GRE scores are normally distributed and have m

valina [46]

Answer:

Z=-2

This value means that the score of Rachel 550 it's 2 deviations below the mean of the population $\mu=600$

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

$\mu=600$ represent the population mean for the Graduate Record Exam (GRE)

$\sigma=25$ represent the population standard deviation for Graduate Record Exam (GRE)

2) Solution to the problem

Let X the random variable that represent the Graduate Record Exam (GRE) of a population, and for this case we know the distribution for X is given by:

$X \sim N(600,25)$