Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26
Answer:
D it
Step-by-step explanation:
We have two equations, A quadratic and a linear equation.
The domain of a linear equation and quadratic equation is all real numbers but since it dealing with time we must make sure the roots or x-intercepts is positive.
Looking at the quadratic equation, we can use the discramnt formula to see if all roots are positve.



The discramnt is greater than zero so there is two distinct real roots. So let check if they are positve
If you graph the equation, it intercepts at two positve roots so it is D
Step-by-step explanation:
there 5^(n+1) + 5^(n+2) = 5^n x 5^1 + 5^n x 5^2 breaking them as x^(a+b) = x^a x x^b
then taking common 5^n from both terms
Do you is playing games notices that the ratio of red tokens to purple tokens is 2 to 3 to count six red tokens John numbers to complete the diagram to the number of purple tokens numbers may be used once more than once or not at all.
Answer: