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eimsori [14]
3 years ago
6

Write and solve a problem that fits the following equation 2x + 18 = 60

Mathematics
2 answers:
Goshia [24]3 years ago
5 0
2x+18=60
-18 -18
2x = 42
÷2. ÷2
x= 21
guapka [62]3 years ago
4 0
Hi there, the opposite of addition is subtraction so we are gonna do -18 on both sides. 60-18=42. So, we have 2x=42. Divide 2 on both sides, 42 divided by 2 is 21. Therefore, x=21
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Question 1
Natasha_Volkova [10]

Given :

⊕   f(x) = 2x + 1

⊕   g(x) = 5x + 4

⊕   m(x) = f(x) - g(x)

⇒   m(x) = (2x + 1) - (5x + 4)

⇒   m(x) = 2x + 1 - 5x - 4

⇒   m(x) = -3x - 3

<u>Answer</u> : C

3 0
3 years ago
Mt. Everest is the highest point in the world at about 8850 meters above sea level. Dead Sea Shore is the lowest point on dry la
NemiM [27]

Answer:

There is a difference of 9268 meters

Step-by-step explanation:

5 0
3 years ago
Help plsss the question says is the relation shown in the table a function use the graph to identify your answer
nirvana33 [79]
If yu don’t know always pick C trust
5 0
3 years ago
roberta deposited 4,790.23 into a saving account with an interest rate of 3.8% compunded twice a year. about how long will it ta
Margarita [4]
The answer to this question would be: 17 years
The <span>interest rate is 3.8% compounded twice a year. The function of the saving account amount would be:
f(x)= </span><span>4,790.23* (1+ 0.038/2)^2x
</span>f(x)= 4,790.23* (1.019)^2x

Then for f(x)= 9,000 the x value would be:
9,000= 4,790.23* (1.019)^2x
9,000/4,790.23= (1.019)^2x
1.8788= (1.019)^2x
<span>2x=34
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7 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cint%20%7Btan%7D%5E%7B3%7D%20x%20%5C%3A%20dx" id="TexFormula1" title=" \int {tan}^{3} x \
r-ruslan [8.4K]

Answer:

\frac{ {tan}^{2}  x}{2}  +  \ln( |cos \: x| ) + C

Step-by-step explanation:

\int {tan}^{3} x \: dx

\int \: tan \: x \times  {tan}^{2} x \: dx

\int \: tan \: x( {sec}^{2} x - 1) \: dx

distribute

\int \: tan \: x  \: {sec}^{2} x - tan \: x \: dx

\int \: tan \: x \:  {sec}^{2} x  \: dx \:  - \int \: tan \: x \: dx

\int \: tan \: x \:  {sec}^{2} x  \: dx \:  - \int \frac{sin \: x}{cos \: x} \: dx

<u>F</u><u>i</u><u>r</u><u>s</u><u>t</u><u> </u><u>i</u><u>n</u><u>t</u><u>e</u><u>g</u><u>r</u><u>a</u><u>n</u><u>d</u>

let tan x = u

du = sec²x dx

<u>S</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u> </u><u>i</u><u>n</u><u>t</u><u>e</u><u>g</u><u>r</u><u>a</u><u>n</u><u>d</u>

let cos x = z

dz = -sin x dx

= \int u \: du \:   -  \int -  \frac{1}{z} dz

=  \frac{ {u}^{2} }{2}   +  \ln( |z| )  + C

=  \color{red}{ \boxed{ \frac{ {tan}^{2}  x}{2}  +  \ln( |cos \: x| ) + C}}

7 0
3 years ago
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