Whats the rest of the question?
Answer:
17.96m/s
Step-by-step explanation:
Based on law of conservation of momentum;
m1u1 +m2u2 =(m1+m2)v
v is the velocities of the car after impact
Substitute the given values
1300(20)+900(15) = (1300+900)v
26000 + 13500 = 2200v
39500 = 2200v
v = 39500/2200
v = 17.96m/s
Hence the speed of the cars after impact is 17.96m/s
Answer:
7:6 boys to girls 6:13 girls to all
Step-by-step explanation:
