<span>Convert 35 mi/h to km/h
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A ball is thrown into the air with a velocity of 33 ft/s. Its height, in feet, after t seconds is given by
1 answer:
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Answer:
the positive slope of the asymptote = 5
Step-by-step explanation:
Given that:
Using the standard form of the equation:
where:
(h,k) are the center of the hyperbola.
and the y term is in front of the x term indicating that the hyperbola opens up and down.
a = distance that indicates how far above and below of the center the vertices of the hyperbola are.
For the above standard equation; the equation for the asymptote is:
where;
is the slope
From above;
(h,k) = 11, 100
= 100
a =
a = 10
b =
b = 2
y = 5x-53 , -5x -57
Since we are to find the positive slope of the asymptote: we have
to be the slope in the equation
=
= 5
Thus, the positive slope of the asymptote = 5