There are
ways of selecting two of the six blocks at random. The probability that one of them contains an error is
So
has probability mass function
These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.
The expected value of finding an error is then
Answer:
0.087
Step-by-step explanation:
Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:
= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:
X₅ ~ Poisson (20 (5/60))
X₅ ~ Poisson (1.6667)
Formula for computing probabilities for Poisson is as follows:
P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!
P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! = (e^-1.6667)((1.6667²)/3!)
P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)
P(X₅= 3) = (2.718^(-1.6667))0.46
P(X₅= 3) = 0.1889×0.46
P(X₅= 3) = 0.086894
P(X₅= 3) = 0.087
Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.
Answer:
22 tickets
Step-by-step explanation:
I assume you're asking about question 2
To find a fraction of a whole number you divide by the bottom number and multiply by the top number. If 2/3 are kids tickets then 1/3 are adult tickets so you divide by 3 and multiply by 1
Answer:
If b=-3 then the first expression is equal to 24 and the second expression is equal to -14.
If b=-2 then the first expression is equal to 8 and the second expression is equal to -36.
If b=10 then the first expression is equal to 440 and the second expression is equal to 324.
Yes, it is true.
Step-by-step explanation:
b=-3:
4b(b+1)=4(-3)(-3+1)=-12(-2)=24
(2b+7)(2b-8)=(2(-3)+7)(2(-3)-8)=(-6+7)(-6-8)=1(-14)=-14
b=-2:
4b(b+1)=4(-2)(-2+1)=-8(-1)=8
(2b+7)(2b-8)=(2(-2)+7)(2(-2)-8)=(-4+7)(-4-8)=3(-12)=-36
b=10:
4b(b+1)=4(10)(10+1)=40(11)=440
(2b+7)(2b-8)=(2(10)+7)(2(10)-8)=(20+7)(20-8)=27(12)=324
