I’m assuming since there isn’t any bar thingys with this, than the 6 is used for both the h and x axis, making it so that it goes right 6 and down 6.
Answer:
the total square inches of the construction paper is 351.63 square inches
Step-by-step explanation:
The computation of the total square inches of the construction paper is shown below;
= (16 × 15 1 ÷ 4) + (10 1 ÷2 × 10 1 ÷ 4)
= (16 × 61 ÷ 4) + (21 ÷ 2 × 41 ÷ 4)
= (16 × 15.25) + (10.5 × 10.25)
= 244 + 107.625
= 351.63 square inches
Hence, the total square inches of the construction paper is 351.63 square inches
We simply added these two
It equals 6 just put it like this: 6/1 nd then divide
Answer: area of the outer part of the rug= 16 -x²
Step-by-step explanation:
Hi, to answer this question we have to apply the next formula:
Area of a square: Side²
Since the area of the rug including the inner square is:
Area of the rug = 4² =16 in²
And the area of the inner square is equal to:
Area if the inner square = x²
To obtain the area of the outer part of the rug we have to subtract the area of the inner square to the area of the rug.
Area of the outer part of the rug= 16 -x²
Feel free to ask for more if needed or if you did not understand something.
Answer:
C(x) = 0.2x^5 - x^2 + 6000
Step-by-step explanation:
Given in the question are restated as follows:
Marginal cos = C'(x) = x^4 - 2x ...................... (1)
Note that marginal cost (C'(x)) refers to the change in the total cost (C(x)) as a result of one more unit increase in the quantity produced. That is, MC refers to the additional cost incurred in order to produce one more unit of a good.
Therefore, TC can be obtained by integrating equation (1) as follows:
C(x) = ∫C'(x) = ∫[x^4 - 2x]dx
C(x) = 1/5x^5 - 2/2x^2 + F ................................ (2)
Where F is the fixed cost. Since the fixed cost is given as $6,000 in the question, we substitute it for F into equation (2) and solve as follows:
C(x) = 0.2x^5 - x^2 + 6000 ......................... (3)
Equation (3) is the total cost function C.