Answer:
34°
Step-by-step explanation:
∠A = arccos(b^2 + c^2 - a^2)/2bc
= 34.016°
Answer:

Step-by-step explanation:

<u>Answer:</u>
A) There are two complex solutions.
<u>Step-by-step explanation:</u>
To know how many solutions a quadratic equation has, calculate the discriminant of the equation.
discriminant = b² - 4ac
where a = coefficient of x²
b = coefficient of x
c = constant of equation
if b² - 4ac > 0 , then equation has 2 real roots
if b² - 4ac = 0 , then equation has 1 real, repeated root
if b² - 4ac < 0 , then equation has 2 complex roots
In this case, discriminant = 9² - 4(-2)(-12)
= -15
As -15 < 0, equation has 2 complex roots.
<span>1. If (-1, y) lies on the graph of y = 3^(x+1), then y = 3^(-1 + 1) = 3^0 = 1
2. If (x, 1/100) lies on the graph of y = 10^x, then 1/100 = 10^x
10^-2 = 10^x
x = -2
3. If (-1, y) lies on the graph of y = 2^2x, then y = 2^2(-1) = 2^(-2) = 1/4
4. The relationship between the graphs of y = 2^x and y = 2^-x is reflections over the y-axis.
5. If (3, y) lies on the graph of y = -(2x), then y = -2(3) = -6
6. All are not exponential
7. If (-2, y) lies on the graph of y = 4^x, then y = 4^(-2) = 1/4^2 = 1/16
8. If (-3, y) lies on the graph of y = 3^-x, then y = 3^-(-3) = 3^3 = 27
9. If (-3, y) lies on the graph of y = 3^x, then y = 3^(-3) = 1/3^3 = 1/27
10. If (-3, y) lies on the graph of y = (1/2)^x, then y = (1/2)^(-3) = 2^3 = 8</span>