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-Dominant- [34]

3 years ago

9

Alex swam a total of 11.5 hours during the work week and then swam a total of 2.6 hours on the weekends. He swam the same number

of hours each week for 7 weeks. What was the total number of hours Alex swam after 7 weeks?

2 answers:

stira [4]3 years ago

7 0

11.7 hours plus 2.6 hours is 14.3 hours. 14.3 hours times seven weeks equals 98.7 hours.

My name is Ann [436]3 years ago

4 0

98.7 hours 11.5+2.6=14.1x7 weeks =98.7 hours

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mafiozo [28]

Answer:

$\frac{x }{2} = 72.8$

8 0

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What's the lowest point of the graph of 10y + 30 = x?

inna [77]

The lowest must be ,,,,,when x=0
so
10y+30=0
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4 years ago

Helen bikes rent bikes for $10 plus $3 per hour. Janice paid $22 to rent a bike. how many hours did she rent the bike

qaws [65]

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8 0

3 years ago

Please help!!!! Will mark brainliest!! 18 points.

andreyandreev [35.5K]

Method 1:

You can use the formula of an area of equilateral triangle:

$A=\dfrac{a^2\sqrt3}{4}$

a - length of side

We have a = 10 yd. Substitute:

$A=\dfrac{10^2\sqrt3}{4}=\dfrac{100\sqrt3}{4}=25\sqrt3\ yd^2\\\\\sqrt3\approx1.7\\\\A=25(1.7)=\boxed{42.5\ yd^2}$

Method 2:

Use the Pythagorean theorem (look at he picture).

$5^2+h^2=10^2$

$25+h^2=100$ <em>subtract 25 from both sides</em>

$h^2=75\to h=\sqrt{75}\\\\h=\sqrt{25\cdot3}\\\\h=\sqrt{25}\cdot\sqrt3\\\\h=5\sqrt3\ yd$

The formula of an area of a trinagle:

$A=\dfrac{1}{2}bh$

b - base

h - height

We have b = 10 yd and h = 5√3 yd. Substitute:

$A=\dfrac{1}{2}(10)(5\sqrt3)=(5)(5\sqrt3)=25\sqrt3\ yd\\\\\sqrt3\approx1.7\\\\A=25(1.7)=\boxed{42.5\ yd^2}$

8 0

3 years ago

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Solve the following linear programming problem.

Reil [10]

Find the intersection point between the 2 restraint equations:

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Substitute back in to find y-value:

y = 30 - 2(12) = 6

P is maximized at point (12,6)

P = 9(12)+9(6) = 162

8 0

3 years ago