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lozanna [386]
4 years ago
11

write the equation that describes the line in slope-intercept form. slope = 4, point (3, −2) is on the line y = 4x 14 y = 4x − 2

y = 4x 10 y = 4x − 14
Mathematics
1 answer:
amid [387]4 years ago
5 0
Equation of a line is given by y - y1 = m(x - x1) where m is the slope and (x1, y1) is any point on the line.

y - (-2) = 4(x - 3)
y + 2 = 4x - 12
y = 4x - 12 - 2
y = 4x - 14
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The answer to your question is below

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A ( 0, -4)            B (2, 0)

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                      (y - y1) = m (x - x1)

                      (y - 0) = 2(x - 2)

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                           0 ≥ 2(2) -4

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                          y ≥ 2x - 4

                         -2 ≥ 2(4) - 4

                         -2 ≥ 8 - 4

                         -2 ≥ 4               This is false

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