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2 years ago

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What is 7 less than y In math

2 answers:

saw5 [17]2 years ago

5 0

Answer:

The algebraic expression is "y - 7".

Step-by-step explanation:

"7 less" means "- 7", so you're subtracting 7 from y. You then write it as "y - 7".

frez [133]2 years ago

3 0

<h3>Answer:</h3>

y-7

<h3>Solution:</h3>

7 less means we subtract 7.
Therefore, the expression "7 less than y" looks like so:
y-7
So we take a number y and subtract 7 from it.

Hope it helps.

Do comment if you have any query.

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In trapezoid ABCD with legs <br> AB<br> and <br> CD<br> , ACAD=23 dm^2. Find AABD.

Fed [463]

In the figure, ABCD is a trapezoid with legs AB and CD.

Join AC and BD.

For the triangle CAD, from the vertex C, draw an altitude CE and for the triangle ABD, from the vertex B, draw an altitude BF.

Clearly, CE = BF = h (say) --- (1)

Note that the base of the triangles CAD and ABD are the same and is AD.

It is given that ar(CAD) = $23dm^{2}$ .

Now, ar(ABD) = $\frac{1}{2}(AD)(BF)$

= $\frac{1}{2}(AD)(CE)$ from (1)

= ar(CAD)

= $23dm^{2}$ .

Hence, area of Δ ABD = $23dm^{2}$ ..

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4 years ago

Lazer Zone charges $15 plus $6 per person to play laser tag. Using the inequality 15+6≤75, find p, the maximum number of people

Murljashka [212]

The answer to your question is 10

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3 years ago

Help asap !<br><br> -100x - 100 = 0<br> -100x = ?<br> x = ?

marin [14]

Answer:

-100x = 10 x = 1

Step-by-step explanation:

I did the math and this is what I got

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3 years ago

Which function can be used to find the number of cells of bacteria in the population at time t

Nonamiya [84]

Answer:

db / dt = kb

this becomes b(t) = Ce^(kt)

C = 100, the initial population

P(1) = 420 = 100 e^(1k)

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a) thus, b(t) = 100 e^(t ln 4.2)

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3 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

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4 years ago