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cricket20 [7]
3 years ago
9

What is the compliment to a 32° angle?

Mathematics
1 answer:
garik1379 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

Since a complimentary angle is two angles who add to 90 degrees the you just ubtract 32 from 90

90-32=58

so 58 is the complimentary

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Lisa family drove 830.76 miles to visit her grandpaerents.Lisa calculated that they used 30.1 gallons og gas .how many miles per
Irina-Kira [14]
830.76/30.1=27.6 miles
7 0
3 years ago
Given klmn is a trapezoid, kl = mn, m<1 = m<2, lm/kn = 8/9, pklmn = 132. Find: the length of the legs
Ilia_Sergeevich [38]

Answer:

The length of legs lm, mn, and lk is 32 while that of kn is 36.

Step-by-step explanation:

The diagram is attached in the answer.

As both the angles are equal thus the two forms isosceles triangles. This is true because the converse of base angle theorem is applicable here. The theorem clearly states that when a trapezoid is divided by the diagonal, it forms two set of angles where m<1=m<2 and m<lmk=m<nmk

This leads the two set of legs such as

\dfrac{lm}{kn}=\dfrac{8}{9}

Or this could be written as

lm=8x\\kn=9x

Now the remaining two sides are given as

lk=lm as this form an isosceles triangle so

lk=8x

Similarly

mn=lm\\

Or

mn=8x

Now the perimeter is given as

\text{perimeter}=lm+mn+kn+lk\\

Here perimeter is given as 132 so this gives:

\text{perimeter}=lm+mn+kn+lk\\132=8x+8x+8x+9x\\132=33x\\x=\dfrac{132}{33}\\x=4

So the four legs are of length as given below:

lm=8x=8\times 4=32\\mn=8x=8\times 4=32\\lk=8x=8\times 4=32\\kn=9x=9\times4=36

So the length of legs lm, mn, and lk is 32 while that of kn is 36.

6 0
3 years ago
What number is less than 337,676?
Sphinxa [80]
Not counting negative numbers there are 337,675 numbers less than 337,676
6 0
3 years ago
I need to get a better grade
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6 0
4 years ago
The ubiquitous 12oz aluminum cans used to distribute drinks in this country have a diameter of approximately 2.75 inches and a h
gayaneshka [121]

Answer:

3.5%

Step-by-step explanation:

The volume of a cylinder = \pi r^2h

<em>r</em> = radius of cylinder,

<em>h</em> = height of cylinder

For the non-optimal can,

<em>r</em> = 2.75/2 = 1.375

<em>h</em> = 5.0

V = \pi(1.375^2)\times 5.0 = 9.453125\pi

<em />

For the optimal can,

<em>d</em>/<em>h</em> = 1,

<em>d</em> = <em>h</em>

2<em>r </em>=<em> h</em>

<em>r</em> = h/2

V = \pi\left(\dfrac{h}{2}\right)^2\times h = \pi\left(\dfrac{h^3}{4}\right)

They have the same volume.

<em />\pi\dfrac{h^3}{4} = 9.453125\pi<em />

h^3 = 37.8125

h=3.36 (This is the height of the optimal can)

r = \dfrac{3.36}{2} = 1.68 (This is the radius of the optimal can)

The area of a cylinder is

<em />A = 2\pi r(r+h)<em />

For the non-optimal can,

A = 2\pi\times\dfrac{2.75}{2}\left(\dfrac{2.75}{2}+5.0\right) = 17.53125\pi

For the optimal can,

A = 2\pi\times1.68\left(1.68+3.36\right) = 16.9344\pi

Amount of aluminum saved, as a percentage of the amount used to make the optimal cans = \dfrac{17.53125\pi - 16.9344\pi}{16.9344\pi}\times 100\% = 3.5\%

5 0
3 years ago
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