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maw [93]
3 years ago
5

Find the perimeter: a polygon with sides 2.1 cm, 2.1 cm, 1 cm, 3.3 cm, and 1 cm

Mathematics
2 answers:
Nostrana [21]3 years ago
7 0

Hello!

P = 2,1cm + 2,1cm + 1cm + 3,3cm + 1cm => P = 4,2cm + 1cm + 3,3cm + 1cm => P = 5,2cm + 3,3cm + 1cm => P = 8,5cm + 1cm => P = 9,5cm

Answer: D. 9,5cm

Good luck! :)

aliya0001 [1]3 years ago
3 0

Answer:

9.5cm

Step-by-step explanation:

To find the perimeter, add up all the sides

2.1 cm+ 2.1 cm+ 1 cm+ 3.3 cm+ 1 cm

9.5cm

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cupoosta [38]

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Step-by-step explanation:

Step 1- combine the coefficients


5 0
3 years ago
What is percent 45 is 72?
agasfer [191]

Answer:

160% of 45 is 72.

Step-by-step explanation:

72/45=1.6

1.6=160%

3 0
3 years ago
I watched a video and didn't get my free answer, can I have some help,
vazorg [7]

Answer:

y + 13 = 5(x + 2)

Step-by-step explanation:

The slope-intercept form of the equation of a line is

y = mx + b,

where m = slope, and b = y-intercept.

From the slope-intercept equation y = 5x - 3, we see that the slope of the line is 3.

The point-slope form of the equation of a line is:

y - y1 = m(x - x1)

where m = slope, and (x1, y1) is a point on the line.

We have point (-2, -13), so x1 = -2, and y1 = -13.

We also have slope 5, so m = 5.

Now we use the coordinates of the given point and the slope in the point-slope equation.

y - (-13) = 5(x - (-2))

We simplify to get

y + 13 = 5(x + 2)

8 0
3 years ago
Question 3<br> Find the equation of the line joining (-2,4) and (3,7)
otez555 [7]

Answer:

y = (3/5)x+26/5 or 5y = 3x+26

Step-by-step explanation:

Applying,

The equation of a line in two point form

(y₂-y₁)/(x₂-x₁) = (y-y₁)/(x-x₁)............... Equation 1

From the question,

Given: y₂ = 7, y₁ = 4, x₂ = 3, x₁ = -2

Substitute these values into equation 1

(7-4)/[3-(-2)] = (y-4)/(x+2)

3/5 = (y-4)/(x+2)

5(y-4) = 3(x+2)

5y-20 = 3x+6

5y = 3x+6+20

5y = 3x+26

y = (3/5)x+26/5

Hence the equation of the line is y = (3/5)x+26/5 or 5y = 3x+26

7 0
2 years ago
In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree
Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Using Law of Cosines in triangle OPQ, we get

\cos P=\dfrac{o^2+q^2-p^2}{2oq}

\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}

\cos P=\dfrac{490000+384400-705600}{868000}

\cos P=\dfrac{168800}{868000}

On further simplification, we get

\cos P=0.19447

P=\cos^{-1}(0.19447)

P=78.786236

P\approx 79

Therefore, the measure of angle P is 79 degrees.

8 0
3 years ago
Read 2 more answers
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