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3 years ago

What are the two steps to solving a proportion

Mathematics

2 answers:

iren [92.7K]3 years ago

8 0

Answer:

Since the cross-products are equal to each other, the two ratios are equivalent.

...

Look at the proportion on the right.

Solve it. (You may use the calculator below.)

Then enter your answer and press the "Enter" or "Return" key on your keyboard.

Press the "New problem" button to get a new problem.

Ghella [55]3 years ago

4 0

Look at the proportion on the right.
Solve it. (You may use the calculator below.)
Then enter your answer and press the "Enter" or "Return" key on your keyboard.
Press the "New problem" button to get a new problem. (Duh.)

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What is the function rule for the line

Sindrei [870]

It’s b. Because the number with out the x is the y-interact which is -2 then to find the other number I look at the graph and find another point and then count the rise/run which is rising 2 running 3 and it’s also positive that’s why it’s b.

7 0

3 years ago

Lim (n/3n-1)^(n-1) n → ∞

n200080 [17]

Looks like the given limit is

$\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1}$

With some simple algebra, we can rewrite

$\dfrac n{3n-1} = \dfrac13 \cdot \dfrac n{n-9} = \dfrac13 \cdot \dfrac{(n-9)+9}{n-9} = \dfrac13 \cdot \left(1 + \dfrac9{n-9}\right)$

then distribute the limit over the product,

$\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1} = \lim_{n\to\infty}\left(\dfrac13\right)^{n-1} \cdot \lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1}$

The first limit is 0, since 1/3ⁿ is a positive, decreasing sequence. But before claiming the overall limit is also 0, we need to show that the second limit is also finite.

For the second limit, recall the definition of the constant, e :

$\displaystyle e = \lim_{n\to\infty} \left(1+\frac1n\right)^n$

To make our limit resemble this one more closely, make a substitution; replace 9/(n - 9) with 1/m, so that

$\dfrac{9}{n-9} = \dfrac1m \implies 9m = n-9 \implies 9m+8 = n-1$

From the relation 9m = n - 9, we see that m also approaches infinity as n approaches infinity. So, the second limit is rewritten as

$\displaystyle\lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1} = \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m+8}$

Now we apply some more properties of multiplication and limits:

$\displaystyle \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m+8} = \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m} \cdot \lim_{m\to\infty}\left(1+\dfrac1m\right)^8 \\\\ = \lim_{m\to\infty}\left(\left(1+\dfrac1m\right)^m\right)^9 \cdot \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)\right)^8 \\\\ = \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)^m\right)^9 \cdot \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)\right)^8 \\\\ = e^9 \cdot 1^8 = e^9$

So, the overall limit is indeed 0:

$\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1} = \underbrace{\lim_{n\to\infty}\left(\dfrac13\right)^{n-1}}_0 \cdot \underbrace{\lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1}}_{e^9} = \boxed{0}$

7 0

3 years ago

Please help!!! i need this done by tonight!! 50 points!!

Vinil7 [7]

The equation of best fit is y = (-22/5)x + 10.

What is an equation of a line?

The equation of a line is given by:

y = mx + c where m is the slope of the line and c is the y-intercept.

Example:

The slope of the line y = 2x + 3 is 2.

The slope of a line that passes through (1, 2) and (2, 3) is 1.

We have,

The following coordinates are given:

Pick two coordinates.

(0, 10) and (25, -100)

The equation of best fit.

y = mx + c

Now,

m = (-100 - 10) / (25 - 0)

m = -110 / 25

m = -22/5

Now,

(0, 10) = (x, y)

10 = (-22/5) x 0 + c

c = 10

Now,

y = mx + c

y = (-22/5)x + 10

Thus,

Using the coordinates the equation of best fit is y = (-22/5)x + 10.

Learn more about equation of a line here:

brainly.com/question/23087740

#SPJ1

5 0

1 year ago

You have 636.3 g of pennies and each penny weighs 3.03g. how many pennies do you have

nalin [4]

Total weight=number of pennies times weight of 1 penny
total weight/weight of 1 penny=number of pennies
636.3/3.03=210

210 pennies

8 0

3 years ago

Helpppp please :) dtchdtgddxxdcrvtgh

sergey [27]

6 cans of paint for a total of 90 dollars spent
I multiplied 120 by .20 to get 24 and subtracted it from 120 to get the amount that still has to be painted which is 96.
96 divided by 16 is 6 which is the number of cans of paint needed to paint the rest. Then just multiply by the cost (15$) and the answer is 90$

3 0

3 years ago

Read 2 more answers