A quarter = 0.25......200 quarters = 200(0.25) = $ 50
a dime = 0.10...150 dimes = 150(0.10) = $ 15
a penny = 0.01....300 pennies = 300(0.01) = $ 3
for a total of : 50 + 15 + 3 = $ 68
Answer:
22v^2 + 5v - 4
Step-by-step explanation:
5v^2 + 9v - 11 + v - 7 + 17v^2 -5v +14
22v^2 + 5v - 4
Answer:
x = 5, x = ![\frac{5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D)
Step-by-step explanation:
Given
+
= 3 ![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
= ![\frac{10}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B3%7D)
= ![\frac{10}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B3%7D)
=
( cross- multiply )
10(x² - 6x + 8) = 3(2x² - 10x + 10) ← distribute both sides
10x² - 60x + 80 = 6x² - 30x + 30 ← subtract 6x² - 30x + 30 from both sides
4x² - 30x + 50 = 0 ( divide through by 2 )
2x² - 15x + 25 = 0 ← in standard form
(2x - 5)(x - 5) = 0 ← in factored form
Equate each factor to zero and solve for x
2x - 5 = 0 ⇒ 2x = 5 ⇒ x = ![\frac{5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D)
x - 5 = 0 ⇒ x = 5
Let the average profit or loss in year 2006 be x millions,
The average profit for the 8-year period, is the total sum of the profits (or losses) of each year, divided by 8:
so we have:
![\displaystyle{ \frac{3.40+2.10+x+0.60+2.10+0.20+1.30+0.75}{8}=1](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20%5Cfrac%7B3.40%2B2.10%2Bx%2B0.60%2B2.10%2B0.20%2B1.30%2B0.75%7D%7B8%7D%3D1%20)
![\displaystyle{\frac{10.45+x}{8}=1](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%5Cfrac%7B10.45%2Bx%7D%7B8%7D%3D1%20)
![10.45+x=8](https://tex.z-dn.net/?f=10.45%2Bx%3D8)
x=8-10.45=-2.45
Answer: the loss in 2006, was 2.45 million dollars
Answer:
1/4
Step-by-step explanation:
-1/2(-5/6 +1/3)
PEMDAS
parentheses first
(-5/6 +1/3)
Get a common denominator
-5/6 + 1/3 *2/2
-5/6 + 2/6 = -3/6 = -1/2
Substitute this back in
-1/2 ( -1/2)
Multiply
1/4