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yawa3891 [41]
3 years ago
9

Jerry has a miniature model of a boat. He knows that the model is 3 3/4 inches wide and 5 1/2 inches long. What is the actual le

ngth of the boat if the actual width is 15 feet
Mathematics
1 answer:
mylen [45]3 years ago
6 0

Answer:

22 feet

Step-by-step explanation:

Change 15 feet into inches using the conversion

1 foot = 12 inches, thus

15 ft = 15 × 12 = 180 inches

scale factor = 180 ÷ 3.75 = 48

Thus the actual dimensions of the boat are 48 times the model.

actual length = 48 × 5.5 = 264 inches = 264 ÷ 12 = 22 feet

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U(8, 9) and V(2, 5) are the endpoints of a line segment. What is the midpoint M of that line segment?
Crazy boy [7]

Answer:

(5, 7 )

Step-by-step explanation:

Given 2 points (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ 0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

here (x₁, y₁ ) = U(8, 9) and (x₂, y₂ ) = V(2, 5), thus

midpoint = [0.5(8 + 2), 0.5(9 + 5) ] = [0.5(10), 0.5(14) ] = (5, 7 )

6 0
4 years ago
one lap around a track is equal to one fourth of a mile. A horse ran a distance of 9 laps in 2 minutes and 30 seconds. What was
Goryan [66]
13.3 repeating all you have to do is convert them into seconds and divide them by nine 
5 0
3 years ago
Peter is saving for a down payment of $50,000 for a new home. Yesterday, he created an equation that models his current savings
garik1379 [7]

Answer:

A. step 4

Step-by-step explanation:

7 0
3 years ago
At the beginning of the month, the value of a stock is $78.35. By the end of the month the value of the stock has changed by a l
liberstina [14]

Answer:

Step-by-step explanation:

Begining of the month, value of stock=$78.35

At the end, the loss = $12.80

Value of stock at the end of the month= the difference between both values

$78.35 - $12.80 = $65.55

8 0
3 years ago
Domain and Range for the function f(x)=5IXI is
shutvik [7]

Answer:

The domain of the function f(x) is:

\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

The range of the function f(x) is:

\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

Step-by-step explanation:

Given the function

f\left(x\right)=5\left|x\right|

Determining the domain:

We know that the domain of the function is the set of input or arguments for which the function is real and defined.  

In other words,  

  • Domain refers to all the possible sets of input values on the x-axis.

It is clear that the function has undefined points nor domain constraints.

Thus, the domain of the function f(x) is:

\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

Determining the range:

We also know that range is the set of values of the dependent variable for which a function is defined.  

In other words,  

  • Range refers to all the possible sets of output values on the y-axis.

We know that the range of an Absolute function is of the form

c|ax+b|+k\:\mathrm{is}\:\:f\left(x\right)\ge \:k

k=0

so

Thus, the range of the function f(x) is:

\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

7 0
3 years ago
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