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kvasek [131]
3 years ago
10

At Store #1 for $625 you can buy 25 pairs of shoes. What is the cost for 1 pair of shoes?

Mathematics
1 answer:
Reptile [31]3 years ago
6 0

Answer:25

Step-by-step explanation:

625/25=25

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What is the equation of the line in slope-intercept form with slope -3/2 and y-intercept -5?
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About Slope Intercept Form:

  • y = mx + b
  • m represents the slope
  • b represents the y-intercept or AKA the starting point

ABOUT PROBLEM:

  • Since -3/2 is the slope, it represents m in Slope Intercept Form
  • Since -5 is the y-intercept, it represents b in Slope Intrecept Form

y = mx + b

y = -3/2x + -5 --- IN Slope Intercept Form


Hope this helps you!!! :)


5 0
3 years ago
Lara has $1,425 in her bank account. Write and solve an equation to show how much money she started with if that amount reflects
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1,425 + 14% = 1,425.14

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Which sequence matches the recursive formula?
goldenfox [79]
Hello:
<span>an = 2an-1 + 5, where a1 = 5
n =2   a2 = 2a1 +5 = 2(5)+5 = 15
</span>n =3  a3 = 2a2 +5 = 2(15)+5 = 35
n =4   a4 = 2a3 +5 = 235)+5 = 75
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4 0
3 years ago
Read 2 more answers
Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
3 years ago
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