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Schach [20]
3 years ago
13

Expand (x+3)(x+2) And can you explain how to do it

Mathematics
2 answers:
shutvik [7]3 years ago
5 0
Just like the other person said, you distribute. An easy way to remember how is the FOIL method. First, Outside, Inside, Last.
So for F, you'd multiply x and x, making x^2. For O, you'd multiply the first x and the 2, which gives you 2x, then for I, multiply the 3 and the second x, and you get 3x from that. Finally, for the L, multiply the 3 and 2, which is 6.
When the whole thing is "foiled," you end up with
x^2 + 2x + 3x + 6.
To put it in its simplest form, combine like terms. In this case, the 2x and 3x.
When you're finished, the expanded form should look like
x^2 + 5x + 6.
I hope that helped!
DanielleElmas [232]3 years ago
3 0
You multiply the two together
x times x equals x squared ( x^2) the x times 2 which equals 2x, then multiply the 3 and x to get 3x and multiply 3 times 2 = 6
so now your problem looks like x[tex] x^{2} + 2x +3x +6 ( now combine like terms) which gives you x^{2} +5x +6, and thats the answer
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