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2 years ago

9

The sum of a number, n, and a number 5 is larger than it is 41. Which of the following equations could be used to solve for the

number?
1. n+5n=41
2. n+n+5=41
3. 5(n+1)=41
4. 5n+n+1=41

1 answer:

Allisa [31]2 years ago

5 0

The answer is A hope this helps

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Then multiply 300*0.45
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"a pollster wishes to estimate the number of left-handed scientists. how large of a sample is needed in order to be 98% confiden

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The sample size should be 250.

Our margin of error is 4%, or 0.04. We use the formula

$\text{ME}=z\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$

To find the z-score:
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Subtract from 1: 1-0.98 = 0.02
Divide both sides by 2: 0.02/2 = 0.01
Subtract from 1: 1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value has a z-score of approximately 2.33. Using this, our margin of error and our proportion, we have:

$0.04=2.33\sqrt{\frac{0.08(1-0.08)}{n}}
\\
\\0.04=2.33\sqrt{\frac{0.08(0.92)}{n}}$

Divide both sides by 2.33:
$\frac{0.04}{2.33}=\sqrt{\frac{0.08(0.92)}{n}}$

Square both sides:
$(\frac{0.04}{2.33})^2=\frac{0.08(0.92)}{n}$

Multiply both sides by n:
$(\frac{0.04}{2.33})^2n=0.08(0.92)$

Divide both sides to isolate n:
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2 years ago